java.lang.NumberFormatException：需要一个整数，但在第 1 行第 8454 列处为 0.6
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java.lang.NumberFormatException: Expected an int but was 0.6 at line 1 column 8454
提问by DJ-DOO
I'm using the retrofit library for my calls in a demo project.
我在演示项目中使用改造库进行调用。
I received the following error:
我收到以下错误：
java.lang.NumberFormatException: Expected an int but was 0.6 at line 1 column 8454 path $.result.results.ads[2].acres
java.lang.NumberFormatException: 预期为 int 但在第 1 行第 8454 列路径 $.result.results.ads[2].acres 处为 0.6
I under stand that this is down to GSON.
我明白这取决于 GSON。
I will show you the JSON it's getting caught in:
我将向您展示它被捕获的 JSON：
{
"ad_id":739580087654,
"property_type":"site",
"house_type":"",
"selling_type":"private-treaty",
"price_type":"",
"agreed":0,
"priority":2,
"description":"Beautiful elevated 0.6 acre site - zoned residential - and within easy walk to this popular and scenic coastal village\r\n\r\n\r\nthe site area is zoned residential ( i.e. can be constructed on for residential home) and has beautiful coastal views\r\n\r\nSpiddal is an exceptionally popular location , just 8 miles west of Galway City but the area has not been over developed.\r\n\r\nAll services and family amenities are location in the village centre.\r\n\r\n",
"price":135000,
"bedrooms":null,
"bathrooms":null,
"tax_section":"0",
"square_metres":0,
"acres":0.6, <----------------------TRIPPING UP HERE
"features":[
"Zoned residential",
"within easy walk of coastal village of Spiddal",
"with coastal views"
],
"ber_rating":"",
"ber_code":"",
"ber_epi":0,
"city":"",
"general_area":"Connemara",
"postcode":null,
"latlon_accuracy":1,
"main_email":"",
"cc_email":"",
"auction_address":"",
"start_date":1384425002,
"listing_date":1384425002,
"agreed_date":0,
"auction_date":0,
"tags":1
},
I'm not that experienced with Retrofit so decided to learn and integrate on this project.
我对 Retrofit 没有那么丰富的经验，所以决定学习和整合这个项目。
Would anyone have any suggestions?
有人会有什么建议吗？
I don't have any control over the JSON being sent down.
我对发送的 JSON 没有任何控制权。
回答by ayanokouji
Try using a floator doubleinstead of an int; 0.6is not an integer, it is a decimal. Note that java automatically interprets decimals as doubles; an example of a float would be 0.6f.
尝试使用float或double代替int; 0.6不是整数，它是小数。请注意，java 自动将小数解释为doubles; 浮动的一个例子是0.6f。
回答by Msp
That's because the parser is expecting an intwhereas the actual value it got was float. What you can do is, change that value's type from intto floatin your model.
那是因为解析器期望的是 ，int而它得到的实际值是float。您可以做的是，在模型中将该值的类型从 更改int为float。
This might cause problems in your code wherever you are using that value. You can solve it by casting that float value to an integer.
无论您在何处使用该值，这都可能导致代码出现问题。您可以通过将该浮点值转换为整数来解决它。
