在 Windows 中使用子程序 Popen.send_signal(CTRL_C_EVENT) 时如何达到预期的结果？
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How to achieve desired results when using the subprocees Popen.send_signal(CTRL_C_EVENT) in Windows?
提问by Mario
In python 2.7 in windows according to the documentation you can send a CTRL_C_EVENT (Python 2.7 Subprocess Popen.send_signal documentation).However when I tried it I did not receive the expected keyboard interrupt in the subprocess.
根据文档，在 Windows 中的 python 2.7 中，您可以发送 CTRL_C_EVENT （Python 2.7 Subprocess Popen.send_signal 文档）。但是，当我尝试它时，我没有在子进程中收到预期的键盘中断。
This is the sample code for for the parent process:
这是父进程的示例代码：
# FILE : parentProcess.py
import subprocess
import time
import signal
CREATE_NEW_PROCESS_GROUP = 512
process = subprocess.Popen(['python', '-u', 'childProcess.py'],
stdin=subprocess.PIPE,
stdout=subprocess.PIPE,
stderr=subprocess.STDOUT,
universal_newlines=True,
creationflags=CREATE_NEW_PROCESS_GROUP)
print "pid = ", process.pid
index = 0
maxLoops = 15
while index < maxLoops:
index += 1
# Send one message every 0.5 seconds
time.sleep(0.5)
# Send data to the subprocess
process.stdin.write('Bar\n')
# Read data from the subprocess
temp = process.stdout.readline()
print temp,
if (index == 10):
# Send Keyboard Interrupt
process.send_signal(signal.CTRL_C_EVENT)
This is the sample code for the child proceess:
这是子进程的示例代码：
# FILE : childProcess.py
import sys
while True:
try:
# Get data from main process
temp = sys.stdin.readline()
# Write data out
print 'Foo ' + temp,
except KeyboardInterrupt:
print "KeyboardInterrupt"
If I run the file parentProcess.py I expect to get "Foo Bar" ten times then a "KeyboardInterrupt" followed by "Foo Bar" 4 times but I get "Foo Bar" 15 times instead.
如果我运行文件 parentProcess.py，我希望得到“Foo Bar”十次，然后是“KeyboardInterrupt”，然后是“Foo Bar”4 次，但我得到“Foo Bar”15 次。
Is there a way to get the CTRL_C_EVENT to behave as a keyboard interrupt just as SIGINT behaves in Linux?
有没有办法让 CTRL_C_EVENT 像 SIGINT 在 Linux 中的行为一样充当键盘中断？
After doing some reading I found some information that seems to contradic the python documentation regarding CTRL_C_EVENT, in particular it says that
在做了一些阅读之后，我发现了一些似乎与关于 CTRL_C_EVENT 的 python 文档相矛盾的信息，特别是它说
CTRL_C_EVENT 0 Generates a CTRL+C signal. This signal cannot be generated for process groups
CTRL_C_EVENT 0 生成 CTRL+C 信号。无法为进程组生成此信号
The following site provide more inforamtion about creation flags: Process Creation Flags.
以下站点提供了有关创建标志的更多信息： 进程创建标志。
回答by Craig McDaniel
This method of signal handling by subprocesses worked for me on both Linux and Windows 2008, both using Python 2.7.2, but it uses Ctrl-Break instead of Ctrl-C. See the note about process groups and Ctrl-C in http://msdn.microsoft.com/en-us/library/ms683155%28v=vs.85%29.aspx.
这种由子进程处理信号的方法在 Linux 和 Windows 2008 上都对我有用，都使用 Python 2.7.2，但它使用 Ctrl-Break 而不是 Ctrl-C。请参阅http://msdn.microsoft.com/en-us/library/ms683155%28v=vs.85%29.aspx 中有关进程组和 Ctrl-C 的说明。
catcher.py:
捕手.py：
import os
import signal
import sys
import time
def signal_handler(signal, frame):
print 'catcher: signal %d received!' % signal
raise Exception('catcher: i am done')
if hasattr(os.sys, 'winver'):
signal.signal(signal.SIGBREAK, signal_handler)
else:
signal.signal(signal.SIGTERM, signal_handler)
print 'catcher: started'
try:
while(True):
print 'catcher: sleeping...'
time.sleep(1)
except Exception as ex:
print ex
sys.exit(0)
thrower.py:
投掷者.py：
import signal
import subprocess
import time
import os
args = [
'python',
'catcher.py',
]
print 'thrower: starting catcher'
if hasattr(os.sys, 'winver'):
process = subprocess.Popen(args, creationflags=subprocess.CREATE_NEW_PROCESS_GROUP)
else:
process = subprocess.Popen(args)
print 'thrower: waiting a couple of seconds for catcher to start...'
time.sleep(2)
print 'thrower: sending signal to catch'
if hasattr(os.sys, 'winver'):
os.kill(process.pid, signal.CTRL_BREAK_EVENT)
else:
process.send_signal(signal.SIGTERM)
print 'thrower: i am done'
回答by sherpya
try with
尝试
win32api.GenerateConsoleCtrlEvent(CTRL_C_EVENT, pgroupid)
or
或者
win32api.GenerateConsoleCtrlEvent(CTRL_BREAK_EVENT, pgroupid)
references:
参考：
http://docs.activestate.com/activepython/2.5/pywin3/win32process_CREATE_NEW_PROCESS_GROUP.html
http://docs.activestate.com/activepython/2.5/pywin3/win32process_CREATE_NEW_PROCESS_GROUP.html
http://msdn.microsoft.com/en-us/library/ms683155%28v=vs.85%29.aspx
http://msdn.microsoft.com/en-us/library/ms683155%28v=vs.85%29.aspx
read info about dwProcessGroupId, the groupid should be the same of the process id
读取有关 dwProcessGroupId 的信息，groupid 应该与进程 id 相同
