Java Retrofit 2.0 抛出“IllegalArgumentException：@Field 参数只能与表单编码一起使用”。如何进行正确的 API 查询并修复它？
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Retrofit 2.0 throwing "IllegalArgumentException: @Field parameters can only be used with form encoding". How to do right API query and fix it?
提问by y07k2
My problem is that I don't know how to start using Retrofit 2.0 with received API- mentioned below...
我的问题是我不知道如何开始使用带有接收到的 API 的 Retrofit 2.0- 下面提到...
Firstly, I need to username, password, fbID (optional), gmailID (optional), twitID (optional), gender, birthDate, location (not required - if long and lat has values), longitude (optional), latitude (optional), profileImage (optional).
首先，我需要用户名、密码、fbID（可选）、gmailID（可选）、twitID（可选）、性别、出生日期、位置（不需要 - 如果 long 和 lat 有值）、经度（可选）、纬度（可选） , profileImage（可选）。
When all parameters are good - receive status = true.
If not - receive status = falseand required parameters which are wrong (e.g. mail is already taken)
当所有参数都正常时接收status = true。如果不是 - 接收status = false和必需的参数是错误的（例如邮件已经被占用）
So I can receive
status = trueor
status = falseand array with max 5 parameters (username, email, password, gender, birthDate).
所以我可以接收
最多 5 个参数（用户名、电子邮件、密码、性别、出生日期）的status = trueor
status = false和数组。
I tried this API Interface:
我试过这个API Interface：
public interface AuthRegisterUserApi {
@PUT()
Call<AuthRegisterUserModel> getStatus(
@Field("username") String username,
@Field("email") String email,
@Field("password") String password,
@Field("fbID") String fbID,
@Field("gmailID") String gmailID,
@Field("twitID") String twitID,
@Field("gender") String gender,
@Field("birthDate") String birthDate,
@Field("location") String location,
@Field("longitude") String longitude,
@Field("latitude") String latitude,
@Field("profileImage") String profileImage
);
class Factory {
private static AuthRegisterUserApi service;
public static AuthRegisterUserApi getInstance() {
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(ApiConstants.REGISTER_URL)
.addConverterFactory(GsonConverterFactory.create())
.build();
service = retrofit.create(AuthRegisterUserApi.class);
return service;
}
}
}
with this API models (Pastebin.com)
and this code in Activity:
和这段代码Activity：
AuthRegisterUserApi.Factory.getInstance()
.getStatus(
usernameEditText.getText().toString(),
emailEditText.getText().toString(),
passwordEditText.getText().toString(),
"", "", "",
(maleRadioButton.isChecked() ? "male" : "female"),
mYear + "-" + mMonth+1 + "-" + mDay,
(geoLocationToggleButton.isChecked() ? geoLocationEditText.getText().toString() : ""),
(!geoLocationToggleButton.isChecked() ? "50" : ""),
(!geoLocationToggleButton.isChecked() ? "50" : ""),
"")
.enqueue(new Callback<AuthRegisterUserModel>() {
@Override
public void onResponse(Call<AuthRegisterUserModel> call, Response<AuthRegisterUserModel> response) {
if(response.isSuccessful()) {
if (response.body().isStatus()) {
showToast(getApplicationContext(), "Registration ok.");
} else {
response.body().getInfo().getUsername();
}
}
}
@Override
public void onFailure(Call<AuthRegisterUserModel> call, Throwable t) {
}
});
I have error: java.lang.IllegalArgumentException: @Field parameters can only be used with form encoding. (parameter #1) for method AuthRegisterUserApi.getStatus
我有错误： java.lang.IllegalArgumentException: @Field parameters can only be used with form encoding. (parameter #1) for method AuthRegisterUserApi.getStatus
I tried to register user using Postman and it works when I used option Body-> x-www-form-urlencoded.
我尝试使用 Postman 注册用户，当我使用 option Body->时它可以工作x-www-form-urlencoded。
How can I create I registerquery to this API?Change @Fieldto something else? I have got this error always...
如何创建register对此 API 的查询？换@Field别的？我总是有这个错误...
EDIT: Need to change API Interfaceto this:
编辑：需要更改API Interface为：
public interface AuthRegisterUserApi {
@FormUrlEncoded
@PUT("/api/register")
Call<AuthRegisterUserModel> getStatus(
@Field("username") String username,
@Field("email") String email,
@Field("password") String password,
@Field("fbID") String fbID,
@Field("gmailID") String gmailID,
@Field("twitID") String twitID,
@Field("gender") String gender,
@Field("birthDate") String birthDate,
@Field("location") String location,
@Field("longitude") String longitude,
@Field("latitude") String latitude,
@Field("profileImage") String profileImage
);
class Factory {
private static AuthRegisterUserApi service;
public static AuthRegisterUserApi getInstance() {
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(ApiConstants.BASE_URL)
.addConverterFactory(GsonConverterFactory.create())
.build();
service = retrofit.create(AuthRegisterUserApi.class);
return service;
}
}
}
BASE_URL = http://ip_address:8400for me...
BASE_URL = http://ip_address:8400为了我...
But still got error: Response.rawResponse = Response{protocol=http/1.1, code=400, message=Bad Request, url=http://ip_address:8400/api/register}. Using Postman with the same data I received code=201 Created. Don't know why...
但仍然有错误：Response.rawResponse = Response{protocol=http/1.1, code=400, message=Bad Request, url=http://ip_address:8400/api/register}. 使用 Postman 和我收到的相同数据 code=201 Created。不知道为什么...
采纳答案by y07k2
The problem was because I try to PUTe.g. longitude\ latitude\ locationwith no value - empty String.
问题是，因为我尝试PUT如longitude\ latitude\location没有价值-空String。
I mean - there was a problem on API side. So to avoid that I changed method to this:
我的意思是 - API 方面存在问题。所以为了避免我把方法改成这样：
@FormUrlEncoded
@PUT(ApiConstants.REGISTER_URL_PART)
Call<RegisterModel> registerUser(
@Field("username") String username,
@Field("email") String email,
@Field("password") String password,
@Field("fbID") String fbID,
@Field("gmailID") String gmailID,
@Field("twitID") String twitID,
@Field("gender") String gender,
@Field("birthDate") String birthDate,
@Nullable @Field("location") String location,
@Nullable @Field("longitude") String longitude,
@Nullable @Field("latitude") String latitude,
@Field("profileImage") String profileImage
);
Now, when I go no value for one of them, I simply don't enclose this field.
现在，当我对其中一个没有任何价值时，我只是不附上这个字段。
回答by Raphael Teyssandier
Your request is not encoded right, but are postman, so do change that :
您的请求编码不正确，而是邮递员，因此请更改：
@FormUrlEncoded
@PUT("/api/register")
Call<AuthRegisterUserModel> getStatus(
@Field("username") String username,
@Field("email") String email,
@Field("password") String password,
@Field("fbID") String fbID,
@Field("gmailID") String gmailID,
@Field("twitID") String twitID,
@Field("gender") String gender,
@Field("birthDate") String birthDate,
@Field("location") String location,
@Field("longitude") String longitude,
@Field("latitude") String latitude,
@Field("profileImage") String profileImage);
Tell me if it's ok.
告诉我是否可以。
回答by Saulo Aguiar
I got a similar error message and I noticed that in my interface definition I missed the @ForUrlEncoded annotation - on top of the rest call that will use the form part, which seems to be the same thing you did at the first posted code block. Take a look at it.
我收到了一个类似的错误消息，我注意到在我的接口定义中我错过了 @ForUrlEncoded 注释 - 在将使用表单部分的其余调用之上，这似乎与您在第一个发布的代码块中所做的相同。看一看。
Hope this helps.
希望这可以帮助。
回答by Rajesh.k
you just missed @FormUrlEncodedabove your Rest method call.
你刚刚错过了@FormUrlEncoded上面的 Rest 方法调用。
