Html XPath 从 IMG 标签解析“SRC”？
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XPath to Parse "SRC" from IMG tag?
提问by dMix
Right now I successfully grabbed the full element from an HTML page with this:
现在我成功地从一个 HTML 页面中抓取了完整的元素：
//img[@class='photo-large']
for example it would return this:
例如它会返回这个：
<img src="http://example.com/img.jpg" class='photo-large' />
But I only need the SRC url (http://example.com/img.jpg). Any help?
但我只需要 SRC url ( http://example.com/img.jpg)。有什么帮助吗？
回答by Jeff Yates
You are so close to answering this yourself that I am somewhat reluctant to answer it for you. However, the following XPath should provide what you want (provided the source is XHTML, of course).
你这么接近自己回答这个问题，我有点不愿意为你回答。但是，以下 XPath 应该提供您想要的（当然，前提是源是 XHTML）。
//img[@class='photo-large']/@src
For further tips, check out W3 Schools. They have excellent tutorials on such things and a great reference too.
如需更多提示，请查看W3 学校。他们有关于这些东西的优秀教程和很好的参考。
回答by andre-r
Using Hpricotthis works:
使用Hpricot这有效：
doc.at('//img[@class="photo-large"]')['src']
In case you have more than one image, the following gives an array:
如果您有多个图像，以下给出了一个数组：
doc.search('//img[@class="photo-large"]').map do |e| e['src'] end
However, Nokogiriis many times fasterand it “can be used as a drop in replacement”for Hpricot.
Here the version for Nokogiri, in which this XPath for selecting attributes works:
然而，引入nokogiri是快很多倍，它“可以作为替代的下降”的角度来说，Hpricot。
这是 Nokogiri 的版本，用于选择属性的 XPath 在其中起作用：
doc.at('//img[@class="photo-large"]/@src').to_s
or for many images:
或对于许多图像：
doc.search('//img[@class="photo-large"]/@src').to_a
回答by nithish peddi
//img/@src
//img/@src
you can just go with this if you want a link of the image.
如果你想要图像的链接，你可以使用这个。
example:
例子：
<img alt="" class="avatar width-full rounded-2" height="230" src="https://avatars3.githubusercontent.com/...;s=460" width="230">
