Javascript 如何使用 Gulp 复制多个文件并保持文件夹结构
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/30067942/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to copy multiple files and keep the folder structure with Gulp
提问by NullPoiиteя
I am trying to copy files from one folder to another folder using Gulp:
我正在尝试使用 Gulp 将文件从一个文件夹复制到另一个文件夹:
gulp.task('move-css',function(){
return gulp.src([
'./source/css/one.css',
'./source/other/css/two.css'
]).pipe(gulp.dest('./public/assets/css/'));
});
The above code is copying one.css& two.cssto the public/assets/cssfolder.
上面的代码是将one.css&复制two.css到public/assets/css文件夹中。
And if I use gulp.src('./source/css/*.css')it will copy all CSS files to the public/assets/cssfolder which is not what I want.
如果我使用gulp.src('./source/css/*.css')它会将所有 CSS 文件复制到public/assets/css我不想要的文件夹中。
How do I select multiple files and keep the folder structure?
如何选择多个文件并保持文件夹结构?
回答by Anulal S
To achieve this please specify base.
要实现这一点,请指定base。
? base- Specify the folder relative to the cwd. Default is where the glob begins. This is used to determine the file names when saving in
.dest()
? base- 指定相对于 cwd 的文件夹。默认是 glob 开始的地方。这用于确定保存时的文件名
.dest()
In your case it would be:
在您的情况下,它将是:
gulp.task('move-css',function(){
return gulp.src([
'./source/css/one.css',
'./source/other/css/two.css'
], {base: './source/'})
.pipe(gulp.dest('./public/assets/'));
});
Folder structure:
文件夹结构:
.
├── gulpfile.js
├── source
│ ├── css
│ └── other
│ └── css
└── public
└── assets
回答by AlejandroJSR7
I use gulp-flatten and use this configuration:
我使用 gulp-flatten 并使用以下配置:
var gulp = require('gulp'),
gulpFlatten = require('gulp-flatten');
var routeSources = {
dist: './public/',
app: './app/',
html_views: {
path: 'app/views/**/*.*',
dist: 'public/views/'
}
};
gulp.task('copy-html-views', task_Copy_html_views);
function task_Copy_html_views() {
return gulp.src([routeSources.html_views.path])
.pipe(gulpFlatten({ includeParents: 1 }))
.pipe(gulp.dest(routeSources.html_views.dist));
}
And there you can see the documentation about gulp-flatten: Link
在那里你可以看到关于 gulp-flatten 的文档:链接

