python 如何在python中将字符串与二进制值连接起来？
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How to concatenate strings with binary values in python?
提问by stefanB
What's the easiest way in python to concatenate string with binary values ?
python 中将字符串与二进制值连接的最简单方法是什么？
sep = 0x1
data = ["abc","def","ghi","jkl"]
Looking for result data "abc0x1def0x1ghi0x1jkl"with the 0x1 being binary value not string "0x1".
寻找"abc0x1def0x1ghi0x1jkl"0x1 是二进制值而不是字符串“0x1”的结果数据。
回答by pdc
I think
我认为
joined = '\x01'.join(data)
should do it. \x01is the escape sequence for a byte with value 0x01.
应该这样做。\x01是值为 0x01 的字节的转义序列。
回答by ricree
The chr() function will have the effect of translating a variable into a string with the binary value you are looking for.
chr() 函数的作用是将变量转换为具有您要查找的二进制值的字符串。
>>> sep = 0x1
>>> sepc = chr(sep)
>>> sepc
'\x01'
The join() function can then be used to concat a series of strings with your binary value as a separator.
然后可以使用 join() 函数将一系列字符串与您的二进制值作为分隔符连接起来。
>>> data = ['abc']*3
>>> data
['abc', 'abc', 'abc']
>>> sepc.join(data)
'abc\x01abc\x01abc'
回答by Steven Hatzakis
I know this isn't the best method, but another way that could be useful in different context for the same question is:
我知道这不是最好的方法，但是对于同一问题在不同上下文中可能有用的另一种方法是：
>>> x=(str(bin(0b110011000)))
>>> b=(str(bin(0b11111111111)))
>>> print(x+b)
0b1100110000b11111111111
And if needed, to remove the left-most two bits of each string (i.e. 0b pad) the slice function [2:]with a value of 2 works:
如果需要，要删除每个字符串最左边的两位（即 0b pad），[2:]值为 2的 slice 函数起作用：
>>> x=(str(bin(0b110011000)[2:]))
>>> b=(str(bin(0b11111111111)[2:]))
>>> print(x+b)
11001100011111111111
