在 PHP 中部分隐藏电子邮件地址
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Partially hide email address in PHP
提问by Bluemagica
I am building a simple friend/buddy system, and when someone tries to search for new friends, I want to show partially hidden email addresses, so as to give an idea about who the user might be, without revealing the actual details.
我正在构建一个简单的朋友/好友系统，当有人尝试搜索新朋友时，我想显示部分隐藏的电子邮件地址，以便在不透露实际细节的情况下了解用户可能是谁。
So I want [email protected]to become abcdl******@hotmail.com.
所以我想[email protected]成为abcdl******@hotmail.com.
As a test I wrote:
作为测试，我写道：
<?php
$email = "[email protected]";
$em = explode("@",$email);
$name = $em[0];
$len = strlen($name);
$showLen = floor($len/2);
$str_arr = str_split($name);
for($ii=$showLen;$ii<$len;$ii++){
$str_arr[$ii] = '*';
}
$em[0] = implode('',$str_arr);
$new_name = implode('@',$em);
echo $new_name;
This works, but I was wondering if there was any easier/shorter way of applying the same logic? Like a regex maybe?
这有效，但我想知道是否有任何更简单/更短的方法来应用相同的逻辑？也许像正则表达式？
回答by msturdy
here's something quick:
这里有一些快速的东西：
function obfuscate_email($email)
{
$em = explode("@",$email);
$name = implode('@', array_slice($em, 0, count($em)-1));
$len = floor(strlen($name)/2);
return substr($name,0, $len) . str_repeat('*', $len) . "@" . end($em);
}
// to see in action:
$emails = ['"Abc\@def"@iana.org', '[email protected]'];
foreach ($emails as $email)
{
echo obfuscate_email($email) . "\n";
}
echoes:
回声：
"Abc\*****@iana.org
abcdl*****@hotmail.com
uses substr()and str_repeat()
回答by Hein Andre Gr?nnestad
Here's my alternate solution for this.
这是我对此的替代解决方案。
I wouldn't use the exact number of mask characters to match the original length of the email, but rather use a fixed length mask for privacy reasons. I would also set the maximum allowed characters to show as well as never show more than half of the email. I would also mask all emails less than a minimum length.
我不会使用确切数量的掩码字符来匹配电子邮件的原始长度，而是出于隐私原因使用固定长度的掩码。我还会设置允许显示的最大字符数，以及从不显示超过一半的电子邮件。我还会屏蔽所有小于最小长度的电子邮件。
With those rules in mind, here's my function with optional parameters:
考虑到这些规则，这是我的带有可选参数的函数：
function maskEmail($email, $minLength = 3, $maxLength = 10, $mask = "***") {
$atPos = strrpos($email, "@");
$name = substr($email, 0, $atPos);
$len = strlen($name);
$domain = substr($email, $atPos);
if (($len / 2) < $maxLength) $maxLength = ($len / 2);
$shortenedEmail = (($len > $minLength) ? substr($name, 0, $maxLength) : "");
return "{$shortenedEmail}{$mask}{$domain}";
}
Tests:
测试：
$email = "";
$tests = [];
for ($i=0; $i < 22; $i++) {
$email .= chr(97 + $i);
$tests[] = $email . " -> " . maskEmail("{$email}@example.com");
}
print_r($tests);
Results:
结果：
Array
(
[0] => a -> ***@example.com
[1] => ab -> ***@example.com
[2] => abc -> ***@example.com
[3] => abcd -> ab***@example.com
[4] => abcde -> ab***@example.com
[5] => abcdef -> abc***@example.com
[6] => abcdefg -> abc***@example.com
[7] => abcdefgh -> abcd***@example.com
[8] => abcdefghi -> abcd***@example.com
[9] => abcdefghij -> abcde***@example.com
[10] => abcdefghijk -> abcde***@example.com
[11] => abcdefghijkl -> abcdef***@example.com
[12] => abcdefghijklm -> abcdef***@example.com
[13] => abcdefghijklmn -> abcdefg***@example.com
[14] => abcdefghijklmno -> abcdefg***@example.com
[15] => abcdefghijklmnop -> abcdefgh***@example.com
[16] => abcdefghijklmnopq -> abcdefgh***@example.com
[17] => abcdefghijklmnopqr -> abcdefghi***@example.com
[18] => abcdefghijklmnopqrs -> abcdefghi***@example.com
[19] => abcdefghijklmnopqrst -> abcdefghij***@example.com
[20] => abcdefghijklmnopqrstu -> abcdefghij***@example.com
[21] => abcdefghijklmnopqrstuv -> abcdefghij***@example.com
)
回答by Szymon Marczak
Maybe this is not what you want, but I would go for this:
也许这不是你想要的，但我会这样做：
<?php
/*
Here's the logic:
We want to show X numbers.
If length of STR is less than X, hide all.
Else replace the rest with *.
*/
function mask($str, $first, $last) {
$len = strlen($str);
$toShow = $first + $last;
return substr($str, 0, $len <= $toShow ? 0 : $first).str_repeat("*", $len - ($len <= $toShow ? 0 : $toShow)).substr($str, $len - $last, $len <= $toShow ? 0 : $last);
}
function mask_email($email) {
$mail_parts = explode("@", $email);
$domain_parts = explode('.', $mail_parts[1]);
$mail_parts[0] = mask($mail_parts[0], 2, 1); // show first 2 letters and last 1 letter
$domain_parts[0] = mask($domain_parts[0], 2, 1); // same here
$mail_parts[1] = implode('.', $domain_parts);
return implode("@", $mail_parts);
}
$emails = array(
'[email protected]',
'[email protected]',
'[email protected]',
'[email protected]',
'[email protected]',
'[email protected]',
'[email protected]',
'[email protected]',
'[email protected]'
);
foreach ($emails as $email){
echo '<b>'.$email.'</b><br>'.mask_email($email).'<br><hr>';
}
Result:
结果：
[email protected]
*@*.com
[email protected]
**@**.com
[email protected]
***@***.com
[email protected]
ab*d@aa*a.com
[email protected]
ab**e@aa**a.com
[email protected]
ab***f@aa***a.com
[email protected]
ab****g@aa****a.com
[email protected]
ab*****h@aa*****a.com
[email protected]
ab******i@aa******a.com
回答by Hani
I created a function can help someone
我创建了一个功能可以帮助某人
function hideEmail($email)
{
$mail_parts = explode("@", $email);
$length = strlen($mail_parts[0]);
$show = floor($length/2);
$hide = $length - $show;
$replace = str_repeat("*", $hide);
return substr_replace ( $mail_parts[0] , $replace , $show, $hide ) . "@" . substr_replace($mail_parts[1], "**", 0, 2);
}
hideEmail("[email protected]"); // output: na**@**ample.com
hideEmail("[email protected]"); // output: some*****@**ample.com
You can customize as you want .. something like this (if length is 4 or less display only the first)
您可以根据需要自定义 .. 类似这样的东西（如果长度为 4 或更少，则只显示第一个）
function hideEmail($email) {
$mail_parts = explode("@", $email);
$length = strlen($mail_parts[0]);
if($length <= 4 & $length > 1)
{
$show = 1;
}else{
$show = floor($length/2);
}
$hide = $length - $show;
$replace = str_repeat("*", $hide);
return substr_replace ( $mail_parts[0] , $replace , $show, $hide ) . "@" . substr_replace($mail_parts[1], "**", 0, 2);
}
hideEmail("[email protected]"); // output: n***@**ample.com
hideEmail("[email protected]"); // output: some*****@**ample.com
回答by niki
I'm using this:
我正在使用这个：
function secret_mail($email)
{
$prop=2;
$domain = substr(strrchr($email, "@"), 1);
$mailname=str_replace($domain,'',$email);
$name_l=strlen($mailname);
$domain_l=strlen($domain);
for($i=0;$i<=$name_l/$prop-1;$i++)
{
$start.='x';
}
for($i=0;$i<=$domain_l/$prop-1;$i++)
{
$end.='x';
}
return substr_replace($mailname, $start, 2, $name_l/$prop).substr_replace($domain, $end, 2, $domain_l/$prop);
}
Will output something like: cyxxxxxone@gmxxxxcom
将输出类似：cyxxxxxone@gmxxxxcom
回答by Igoooor
For instance :
例如 ：
substr($email, 0, 3).'****'.substr($email, strpos($email, "@"));
Which will give you something like:
这会给你类似的东西：
abc****@hotmail.com
abc****@hotmail.com
回答by Michael Nguyen
I m using femich answer above and tweak it a bit for my
我正在使用上面的 femich 答案并为我的
function mask_email($email, $char_shown_front = 1, $char_shown_back = 1)
{
$mail_parts = explode('@', $email);
$username = $mail_parts[0];
$len = strlen($username);
if ($len < $char_shown_front or $len < $char_shown_back) {
return implode('@', $mail_parts);
}
//Logic: show asterisk in middle, but also show the last character before @
$mail_parts[0] = substr($username, 0, $char_shown_front)
. str_repeat('*', $len - $char_shown_front - $char_shown_back)
. substr($username, $len - $char_shown_back, $char_shown_back);
return implode('@', $mail_parts);
}
[email protected] -> t*****[email protected]
[email protected] -> t*****[email protected]
you can pass in the number of character to show in the front and in the back
您可以传入要显示在前面和后面的字符数
回答by fedmich
Sometimes its good to show the last charactertoo.
有时显示最后一个字符也很好。
[email protected] becomes A*****[email protected]
[email protected] 变为 A*****[email protected]
I will suggest you keep things simple. Maybe something like this is simple enough https://github.com/fedmich/PHP_Codes/blob/master/mask_email.php
我会建议你保持简单。也许这样的事情很简单 https://github.com/fedmich/PHP_Codes/blob/master/mask_email.php
Masks an email to show first 3 characters and then the last character before the @ sign
屏蔽电子邮件以显示前 3 个字符，然后显示 @ 符号前的最后一个字符
function mask_email( $email ) {
/*
Author: Fed
Simple way of masking emails
*/
$char_shown = 3;
$mail_parts = explode("@", $email);
$username = $mail_parts[0];
$len = strlen( $username );
if( $len <= $char_shown ){
return implode("@", $mail_parts );
}
//Logic: show asterisk in middle, but also show the last character before @
$mail_parts[0] = substr( $username, 0 , $char_shown )
. str_repeat("*", $len - $char_shown - 1 )
. substr( $username, $len - $char_shown + 2 , 1 )
;
return implode("@", $mail_parts );
}
回答by Daud khan
I have a function
我有一个功能
function hide_email($email){
$final_str = '';
$string = explode('@', $email);
$leftlength = strlen($string[0]);
$string2 = explode('.', $string[1]);
$string2len = strlen($string2[0]);
$leftlength_new = $leftlength-1;
$first_letter = substr($string[0], 0,1);
$stars = '';
$stars2 = '';
for ($i=0; $i < $leftlength_new; $i++) {
$stars .= '*';
}
for ($i=0; $i < $string2len; $i++) {
$stars2 .= '*';
}
$stars;
return $final_str .= $first_letter.$stars.'@'.$stars2.'.'.$string2[1];
}
}
echo hide_email('[email protected]');
echo hide_email('[email protected]');
回答by Waqas
There was an issue in case if there would be 1 character before @. I have fixed in below function.
如果@ 之前有1 个字符，则会出现问题。我已经修复了以下功能。
function obfuscate_email($email)
{
$em = explode("@",$email);
if(strlen($em[0])==1){
return '*'.'@'.$em[1];
}
$name = implode(array_slice($em, 0, count($em)-1), '@');
$len = floor(strlen($name)/2);
return substr($name,0, $len) . str_repeat('*', $len) . "@" . end($em);
}
