java 如何从 Retrofit 的 onResponse 函数返回值?

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时间:2020-11-02 22:35:02  来源:igfitidea点击:

How can I return value from function onResponse of Retrofit?

javajsonmethodsretrofit

提问by Cristian Cam G

I'm trying to return a value that i get from onResponsemethod in retrofitcall request, is there a way that i can get that value out of the overrided method? here is my code:

我正在尝试返回一个从调用请求中的onResponse方法获得的值,retrofit有没有办法可以从覆盖的方法中获取该值?这是我的代码:

public JSONArray RequestGR(LatLng start, LatLng end)
    {
       final JSONArray jsonArray_GR;

        EndpointInterface loginService = ServiceAuthGenerator.createService(EndpointInterface.class);    
        Call<GR> call = loginService.getroutedriver();
        call.enqueue(new Callback<GR>() {
            @Override
            public void onResponse(Response<GR> response , Retrofit retrofit)
            {

                 jsonArray_GR = response.body().getRoutes();
//i need to return this jsonArray_GR in my RequestGR method
            }
            @Override
            public void onFailure(Throwable t) {
            }
        });
        return jsonArray_GR;
    }

i can't get the value of jsonArray_GRbecause to be able to use it in onResponsemethod i need to declare it final and i can't give it a value.

我无法获得的值,jsonArray_GR因为为了能够在onResponse方法中使用它,我需要将其声明为 final 并且我不能给它一个值。

回答by torbinsky

The problem is you are trying to synchronously return the value of enqueue, but it is an asynchronous method using a callback so you can't do that. You have 2 options:

问题是您正在尝试同步返回 的值enqueue,但它是使用回调的异步方法,因此您不能这样做。您有 2 个选择:

  1. You can change your RequestGRmethod to accept a callback and then chain the enqueuecallback to it. This is similar to mapping in frameworks like rxJava.
  1. 您可以更改RequestGR方法以接受回调,然后将enqueue回调链接到它。这类似于 rxJava 等框架中的映射。

This would look roughly like:

这大概是这样的:

public void RequestGR(LatLng start, LatLng end, final Callback<JSONArray> arrayCallback)
    {

        EndpointInterface loginService = ServiceAuthGenerator.createService(EndpointInterface.class);    
        Call<GR> call = loginService.getroutedriver();
        call.enqueue(new Callback<GR>() {
            @Override
            public void onResponse(Response<GR> response , Retrofit retrofit)
            {

                 JSONArray jsonArray_GR = response.body().getRoutes();
                 arrayCallback.onResponse(jsonArray_GR);
            }
            @Override
            public void onFailure(Throwable t) {
               // error handling? arrayCallback.onFailure(t)?
            }
        });
    }

The caveat with this approach is it just pushes the async stuff up another level, which might be a problem for you.

这种方法的警告是它只是将异步内容推到另一个级别,这对您来说可能是一个问题。

  1. You can use an object similar to a BlockingQueue, Promiseor an Observableor even your own container object (be careful to be thread safe) that allows you to check and set the value.
  1. 您可以使用类似于 a 的对象BlockingQueuePromise或者Observable甚至是您自己的容器对象(注意线程安全),它允许您检查和设置值。

This would look like:

这看起来像:

public BlockingQueue<JSONArray> RequestGR(LatLng start, LatLng end)
    {
        // You can create a final container object outside of your callback and then pass in your value to it from inside the callback.
        final BlockingQueue<JSONArray> blockingQueue = new ArrayBlockingQueue<>(1);
        EndpointInterface loginService = ServiceAuthGenerator.createService(EndpointInterface.class);    
        Call<GR> call = loginService.getroutedriver();
        call.enqueue(new Callback<GR>() {
            @Override
            public void onResponse(Response<GR> response , Retrofit retrofit)
            {

                 JSONArray jsonArray_GR = response.body().getRoutes();
                 blockingQueue.add(jsonArray_GR);
            }
            @Override
            public void onFailure(Throwable t) {
            }
        });
        return blockingQueue;
    }

You can then synchronously wait for your result in your calling method like this:

然后,您可以像这样在调用方法中同步等待结果:

BlockingQueue<JSONArray> result = RequestGR(42,42);
JSONArray value = result.take(); // this will block your thread

I would highly suggest reading up on a framework like rxJava though.

我强烈建议阅读像 rxJava 这样的框架。