git .gitignore：如何忽略嵌套目录？
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.gitignore: How do I ignore nested directories?
提问by artagnon
I have the following directory structure:
我有以下目录结构：
test/a
test/b/c
test/a/b/Ouput
test/c/d/e/Output
test/f/Output
I want to ignore all the "Output" directories under "test". I tried test/**/Output, but it didn't work. What am I doing wrong?
我想忽略“测试”下的所有“输出”目录。我试过了test/**/Output，但没有用。我究竟做错了什么？
采纳答案by Chin Huang
You said you want the Output/pattern to match only under the test/directory, so in the test/directory, create a .gitignorefile with the contents:
你说你希望Output/模式只在test/目录下匹配，所以在test/目录中，创建一个.gitignore包含内容的文件：
Output/
If you put this pattern in your top-level .gitignorefile, then it will match in alldirectories under the top directory.
如果将此模式放在顶级.gitignore文件中，那么它将在顶级目录下的所有目录中匹配。
回答by Leszek Jasek
Since version 1.8.2(March, 8th 2013), git supports ** in .gitignorefiles, so using test/**/Output/will ignore only Output sub-directories under test directory.
从1.8.2 版本（2013 年 3 月 8 日）开始，git 支持.gitignore文件中的** ，因此使用test/**/Output/将仅忽略 test 目录下的 Output 子目录。
