php php字符串函数在最后一次出现字符之前获取子字符串
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php string function to get substring before the last occurrence of a character
提问by ptamzz
$string = "Hello World Again".
echo strrchr($string , ' '); // Gets ' Again'
Now I want to get "Hello World" from the $string[The substring before the last occurrence of a space ' ' ]. How do I get it??
现在我想从$string[最后一次出现空格 ' ' 之前的子字符串] 中获取“Hello World” 。我怎么得到它？？
采纳答案by sdleihssirhc
This is kind of a cheap way to do it, but you could split, pop, and then join to get it done:
这是一种廉价的方法，但您可以拆分、弹出，然后加入以完成它：
$string = 'Hello World Again';
$string = explode(' ', $string);
array_pop($string);
$string = implode(' ', $string);
回答by meouw
$string = "Hello World Again";
echo substr($string, 0, strrpos( $string, ' ') ); //Hello World
If the character isn't found, nothing is echoed
如果未找到该字符，则不回显任何内容
回答by zaf
One (nice and chilled out) way:
一种（好的和冷静的）方式：
$string = "Hello World Again";
$t1=explode(' ',$string);
array_pop($t1);
$t2=implode(' ',$t1);
print_r($t2);
Other (more tricky) ways:
其他（更棘手的）方法：
$result = preg_replace('~\s+\S+$~', '', $string);
or
或者
$result = implode(" ", array_slice(str_word_count($string, 1), 0, -1));
回答by R T
回答by Till
$myString = "Hello World Again";
echo substr($myString, 0, strrpos($myString, " "));
回答by DaveK
回答by Arvind Bhardwaj
The correct implementation should be:
正确的实现应该是：
$string = "Hello World Again";
$pos = strrpos( $string, ' ');
if ($pos !== false) {
echo substr($string, 0, $pos ); //Hello World
}
Otherwise if the character is not found it will print nothing. See following case:
否则，如果找不到该字符，它将不打印任何内容。见以下案例：
$string = "Hello World Again";
//prints nothing as : is not found and strrpos returns false.
echo substr($string, 0, strrpos( $string, ':') );
回答by Nick
You could just use:
你可以只使用：
$string = "Hello World Again";
echo preg_replace('# [^ ]*$', '', $string);
This will work regardless of whether the character occurs in the string or not. It will also work if the last character is a space.
无论字符是否出现在字符串中，这都将起作用。如果最后一个字符是空格，它也将起作用。
回答by Maciej P?usa
function cutTo($string, $symbol) {
return substr($string, 0, strpos($string, $symbol));
}
