Java Spring MVC 在“/”上打开 index.jsp
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Spring MVC open index.jsp on "/"
提问by bsferreira
How can I open index.jsp using this url http://localhost:8080/myApp/and how can I use an hyperlink like this
<a href="/">HOME</a>and go to index.jsp (http://localhost:8080/myApp/)?
如何使用此 url 打开 index.jsphttp://localhost:8080/myApp/以及如何使用这样的超链接
<a href="/">HOME</a>并转到 index.jsp ( http://localhost:8080/myApp/)？
Here's my web.xml:
这是我的 web.xml：
<display-name>myApp</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:spring/application-config.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>myApp</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>myApp</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
And here is my myApp-servlet.xml:
这是我的 myApp-servlet.xml：
<context:component-scan base-package="org.myApp.com" />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/view/" />
<property name="suffix" value=".jsp" />
</bean>
Thanks in advance!
提前致谢！
采纳答案by Sotirios Delimanolis
Just add a @Controllerwith an appropriate handler method
只需添加一个@Controller适当的处理程序方法
@Controller
public class RootController {
@RequestMapping(value = "/", method = RequestMethod.GET)
public String root() {
return "index";
}
}
assuming index.jspis in /WEB-INF/view.
假设index.jsp在/WEB-INF/view.
