java 如何检查 Web 服务是否可访问？
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How to check if a web service is accessible?
提问by xyz
How can I check if any web service is accessible ?
I can see the list of service also I know the method names present in the web service.But I don't know which parameters the method accepts.
Here is the method present in the web service
如何检查是否可以访问任何 Web 服务？
我可以看到服务列表，我也知道 Web 服务中存在的方法名称。但我不知道该方法接受哪些参数。
这是 Web 服务中存在的方法
public OMElement getChildren(OMElement paramOMElement)
{
Object localObject2 = paramOMElement.toString();
// Some other stuff
}
I tried something like http://machine_name/war_name/services/service_name/getChildren?aand got following error
我尝试了类似的操作http://machine_name/war_name/services/service_name/getChildren?a并出现以下错误
soapenv:Fault>
<faultcode>soapenv:Client</faultcode>
?
<faultstring>
Umarshaller error: Error during unmarshall <getChildren><a></a></getChildren>; nested exception is:
edu.harvard.i2b2.common.exception.I2B2Exception: Umarshaller error: Error during unmarshall <getChildren><a></a></getChildren>; nested exception is:
org.apache.axis2.AxisFault: Umarshaller error: Error during unmarshall <getChildren><a></a></getChildren>; nested exception is:
edu.harvard.i2b2.common.exception.I2B2Exception: Umarshaller error: Error during unmarshall <getChildren><a></a></getChildren>
</faultstring>
<detail/>
</soapenv:Fault>
Is this error mean I am able to access the service but sending wrong arguments ?
Also the service dont have WSDL file.
How can I check whether the service is accessible or how can I find out the exact parameters which are required ?
这个错误是否意味着我可以访问该服务但发送错误的参数？
该服务也没有 WSDL 文件。
如何检查服务是否可访问或如何找出所需的确切参数？
回答by Baz1nga
Well you need to send a request to the service and see if there is a response and there is no exception and thus make sure that the server is running.. Nt comfortable with coding in java but here is the c# excerpt:
好吧，您需要向服务发送请求并查看是否有响应并且没有异常，从而确保服务器正在运行。
function bool CheckIfServiceIsAlive(string url)
{
var isServiceUrlAlive= false;
var req = WebRequest.Create(url);
if (!string.IsNullOrEmpty(proxyServer))
{
var proxy = new WebProxy(proxyServer, 8080) { Credentials = req.Credentials }; //if you need to use a proxy
WebRequest.DefaultWebProxy = proxy;
req.Proxy = proxy;
}
else
{
req.Proxy = new WebProxy();
}
try
{
var response = (HttpWebResponse)req.GetResponse();
isServiceUrlAlive= true;
}
catch (WebException) { }
return isServiceUrlAlive;
There might be easier solutions for java like using the Apache Commons UrlValidatorclass
可能有更简单的 Java 解决方案，例如使用Apache Commons UrlValidator类
UrlValidator urlValidator = new UrlValidator();
urlValidator.isValid("http://<your service url>");
or use a method like this that gets the response code
或使用这样的方法来获取响应代码
public static int getResponseCode(String urlString) throws MalformedURLException, IOException {
URL u = new URL(urlString);
HttpURLConnection huc = (HttpURLConnection) u.openConnection();
huc.setRequestMethod("GET");
huc.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.1.2) Gecko/20090729 Firefox/3.5.2 (.NET CLR 3.5.30729)");
huc.connect();
return huc.getResponseCode();
}
or try this: http://www.java-tips.org/java-se-tips/java.net/check-if-a-page-exists-2.html
或试试这个：http: //www.java-tips.org/java-se-tips/java.net/check-if-a-page-exists-2.html
Tell me which one worked for you..
告诉我哪一个对你有用..
