bash 在所有直接子目录中执行命令
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Execute command in all immediate subdirectories
提问by Zahymaka
I'm trying to add a shell function (zsh) mexecto execute the same command in all immediate subdirectories e.g. with the following structure
我正在尝试添加一个 shell 函数 (zsh)mexec以在所有直接子目录中执行相同的命令，例如具有以下结构
~
-- folder1
-- folder2
mexec pwdwould show for example
mexec pwd会显示例如
/home/me/folder1
/home/me/folder2
I'm using findto pull the immediate subdirectories. The problem is getting the passed in command to execute. Here's my first function defintion:
我正在使用find拉直接子目录。问题是让传入的命令执行。这是我的第一个函数定义：
mexec() {
find . -mindepth 1 -maxdepth 1 -type d | xargs -I'{}' \
/bin/zsh -c "cd {} && $@;";
}
only executes the command itself but doesn't pass in the arguments i.e. mexec ls -albehaves exactly like ls
只执行命令本身，但不传递参数，即mexec ls -al行为完全像ls
Changing the second line to /bin/zsh -c "(cd {} && $@);", mexecworks for just mexec lsbut shows this error for mexec ls -al:
将第二行更改为/bin/zsh -c "(cd {} && $@);",mexec仅适用于mexec ls但显示以下错误mexec ls -al：
zsh:1: parse error near `ls'
Going the exec route with find
使用 find 走 exec 路线
find . -mindepth 1 -maxdepth 1 -type d -exec /bin/zsh -c "(cd {} && $@)" \;
Gives me the same thing which leads me to believe there's a problem with how I'm passing the arguments to zsh. This also seems to be a problem if I use bash: the error shown is:
给了我同样的事情，这让我相信我将参数传递给 zsh 的方式存在问题。如果我使用 bash，这似乎也是一个问题：显示的错误是：
-a);: -c: line 1: syntax error: unexpected end of file
What would be a good way to achieve this?
实现这一目标的好方法是什么？
回答by Inian
Can you try using this simple loop which loops in all sub-directories at one level deep and execute commands on it,
您可以尝试使用这个简单的循环，它会在所有子目录中的一层深度循环并在其上执行命令，
for d in ./*/ ; do (cd "$d" && ls -al); done
(cmd1 && cmd2)opens a sub-shell to run the commands. Since it is a child shell, the parent shell (the shell from which you're running this command) retains its current folder and other environment variables.
(cmd1 && cmd2)打开一个子shell来运行命令。由于它是一个子 shell，父 shell（您从中运行此命令的 shell）保留其当前文件夹和其他环境变量。
Wrap it around in a function in a proper zshscript as
将它包装在一个适当zsh脚本的函数中，如下所示
#!/bin/zsh
function runCommand() {
for d in ./*/ ; do /bin/zsh -c "(cd "$d" && "$@")"; done
}
runCommand "ls -al"
should work just fine for you.
应该适合你。
回答by wilsotc
#!/bin/zsh
# A simple script with a function...
mexec()
{
export THE_COMMAND=$@
find . -type d -maxdepth 1 -mindepth 1 -print0 | xargs -0 -I{} zsh -c 'cd "{}" && echo "{}" && echo "$('$THE_COMMAND')" && echo -e'
}
mexec ls -al
