bash 从linux shell中的文本文件生成二进制文件
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generate a binary file from a text file in linux shell
提问by Alcott
I have a text file a.txt, inside which each line consists of 2 numbers, looks like this:
我有一个文本文件 a.txt，其中每行由 2 个数字组成，如下所示：
1234 5678
Now I want to convert a.txt's content from text into binary, which means the numbers won't be text anymore, but binary representation, which can be viewed by od -tu4.
现在我想将 a.txt 的内容从文本转换为二进制，这意味着数字不再是文本，而是二进制表示，可以通过od -tu4.
How can I do that via bash?
我怎样才能做到这一点bash？
回答by James
Here is a shell script that uses AWK to do what you want. Put the following into a file (hex2bin.awk):
这是一个 shell 脚本，它使用 AWK 来做你想做的事。将以下内容放入文件 (hex2bin.awk)：
#!/usr/bin/awk -f
function dec2bin(n){
for(i=0;i < 4; i++){
printf("%c", n % 256);
n = int(n / 256);
}
}
{ dec2bin(); dec2bin();}
Make the file executable (chmod a+x hex2bin.awk)
使文件可执行 ( chmod a+x hex2bin.awk)
Then run it:
然后运行它：
./hex2bin.awk a.txt | od -tu4
0000000 1234 5678
0000010
This reads in two columns of decimal numbers represented in ASCII and prints them out into 32-bit little endian binary.
这将读取以 ASCII 表示的两列十进制数字，并将它们打印为 32 位小端二进制。
