SQL 如何只显示oracle中的时间?

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/1568406/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-09-01 03:58:59  来源:igfitidea点击:

how to show only the time in oracle?

sqloracleoracle10g

提问by Gold

I have table that has date field. When I run a query, I see this:

我有带有日期字段的表。当我运行查询时,我看到:

01/10/2009 22:10:39

01/10/2009 22:10:39

How can I retrieve only the time (IE: 22:10:39)

我怎样才能只检索时间(IE:22:10:39)

回答by Amirshk

you can try this:

你可以试试这个:

SELECT TO_CHAR(yourval, 'DD-MON-YYYY HH:MI:SS') FROM yourtable;
SELECT TO_CHAR(yourval, 'HH:MI:SS') FROM yourtable;

Edit:as @steven pointed out, to have 24 hours style use

编辑:正如@steven 指出的,要使用 24 小时风格

SELECT TO_CHAR(yourval, 'HH24:MI:SS') FROM yourtable;

回答by Steven

You need the format HH24, since HHis only a 12 hour date.

您需要 format HH24,因为HH它只是一个 12 小时的日期。

select to_char(SYSDATE, 'HH24:MI:SS') from dual

select to_char(YourDateColumn, 'HH24:MI:SS') from YourTable

回答by Henry Gao

SELECT TO_CHAR (SYSDATE, 'hh:mi:ss') FROM DUAL

SELECT TO_CHAR (SYSDATE, 'hh:mi:ss') FROM DUAL

回答by Haid

SELECT TO_CHAR(DATE_COLUMN,'HH24:MI:SS') from TABLE;

从表中选择 TO_CHAR(DATE_COLUMN,'HH24:MI:SS');