C语言 如何将 scanf 用于字符数组输入？
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How to use scanf for a char array input?
提问by cyis
I set a char array of size of 10 and want to check the real size of the input permitted.
我设置了一个大小为 10 的字符数组，并想检查允许输入的实际大小。
I tested
我测试过
123456789; 1234567890; 123456789123456789
123456789; 1234567890; 123456789123456789
Interestingly, all of them passed and got the right output which are
有趣的是，他们都通过了并得到了正确的输出
123456789; 1234567890; 123456789123456789
It confused me a lot because I thought the last two are wrong input.
这让我很困惑，因为我认为最后两个是错误的输入。
Does that make sense or is it a compiler difference?
这是有道理的还是编译器的区别？
This is the code
这是代码
#include <stdio.h>
main()
{
char input[10];
scanf("%s", input);
printf(input);
} '
回答by Gopi
The scanf()with format specifier %sscans the input until a space is encountered. In your case, what you are seeing is undefined behavior.
Your array can hold 10 chars, but you are writing out of its boundaries.
在scanf()与格式说明%s，直到遇到一个空间扫描输入。在您的情况下，您看到的是未定义的行为。您的数组可以容纳 10char秒，但您正在写出它的边界。
While you are getting an expected answer now, this is not always guarnateed and may instead cause a crash.
虽然您现在得到了预期的答案，但这并不总是有保证的，反而可能会导致崩溃。
It is advisable to use a function such as fgets()takes care of buffer overflow.
建议使用诸如fgets()处理缓冲区溢出之类的功能。
回答by Ahmad Yoosofan
You can use
您可以使用
scanf("%9s", input);
