Python 将十六进制数据写入文件
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Writing hex data into a file
提问by Pythonizer
I'm trying to write hex data taken from ascii file to a newly created binary file
我正在尝试将从 ascii 文件中获取的十六进制数据写入新创建的二进制文件
ascii file example:
ascii 文件示例：
98 af b7 93 bb 03 bf 8e ae 16 bf 2e 52 43 8b df
4f 4e 5a e4 26 3f ca f7 b1 ab 93 4f 20 bf 0a bf
82 2c dd c5 38 70 17 a0 00 fd 3b fe 3d 53 fc 3b
28 c1 ff 9e a9 28 29 c1 94 d4 54 d4 d4 ff 7b 40
my code
我的代码
hexList = []
with open('hexFile.txt', 'r') as hexData:
line=hexData.readline()
while line != '':
line = line.rstrip()
lineHex = line.split(' ')
for i in lineHex:
hexList.append(int(i, 16))
line = hexData.readline()
with open('test', 'wb') as f:
for i in hexList:
f.write(hex(i))
Thought hexListholds already hex converted data and f.write(hex(i))should write these hex data into a file, but python writes it with ascii mode
ThoughthexList已经保存了 hex 转换的数据，f.write(hex(i))应该将这些 hex 数据写入文件中，但是 python 以 ascii 方式写入
final output: 0x9f0x2c0x380x590xcd0x110x7c0x590xc90x30xea0x37which is wrong!
最终输出：0x9f0x2c0x380x590xcd0x110x7c0x590xc90x30xea0x37这是错误的！
where is the issue?
问题出在哪里？
采纳答案by falsetru
Use binascii.unhexlify:
>>> import binascii
>>> binascii.unhexlify('9f')
'\x9f'
>>> hex(int('9f', 16))
'0x9f'
import binascii
with open('hexFile.txt') as f, open('test', 'wb') as fout:
for line in f:
fout.write(
binascii.unhexlify(''.join(line.split()))
)
回答by John1024
replace:
代替：
f.write(hex(i))
With:
和：
f.write(chr(i)) # python 2
Or,
或者，
f.write(bytes((i,))) # python 3
Explanation
解释
Observe:
观察：
>>> hex(65)
'0x41'
65should translate into a single byte but hexreturns a four character string. writewill send all four characters to the file.
65应该转换为单个字节，但hex返回一个四个字符的字符串。 write将所有四个字符发送到文件。
By contrast, in python2:
相比之下，在python2中：
>>> chr(65)
'A'
This does what you want: chrconverts the number 65to the character single-byte string which is what belongs in a binary file.
这可以满足您的需求：chr将数字转换65为属于二进制文件的字符单字节字符串。
In python3, chr(i)is replaced by bytes((i,)).
在 python3 中，chr(i)被替换为bytes((i,)).
