使用正则表达式匹配 Laravel 路由中的子字符串
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Using a regex to match a substring in a Laravel route
提问by prograhammer
My URL is: www.foo.com/some-bar-slug-here/page
我的网址是：www.foo.com/some-bar-slug-here/page
I can't get a route to catch if the string "bar" is found in the slug shown above:
如果在上面显示的 slug 中找到字符串“bar”，我将无法获得一条路线：
Route::any('{myslug}/page/', array('as'=>'bar-page', 'uses'=>'Controllers\MyBar@index'))
->where('myslug','/bar/');
If I use the regex expression [0-9A-Za-z\-]+it works, but it doesn't work for /bar/. Any ideas?
如果我使用正则表达式[0-9A-Za-z\-]+它可以工作，但它不适用于/bar/. 有任何想法吗？
回答by prograhammer
I got it working with ^([0-9A-Za-z\-]+)?bar([0-9A-Za-z\-]+)?
我得到它的工作 ^([0-9A-Za-z\-]+)?bar([0-9A-Za-z\-]+)?
So the updated route code looks like this:
所以更新后的路由代码如下所示：
Route::any('{myslug}/page/', array('as'=>'bar-page', 'uses'=>'Controllers\MyBar@index'))
->where('myslug','^([0-9A-Za-z\-]+)?bar([0-9A-Za-z\-]+)?');
Bonus: To make it case insensitive, I do this: ^([0-9A-Za-z\-]+)?(?i)bar([0-9A-Za-z\-]+)?
奖励：为了不区分大小写，我这样做： ^([0-9A-Za-z\-]+)?(?i)bar([0-9A-Za-z\-]+)?
Note: If you are using a copy of this route further down in the your routes file, but searching for a different sub-string then you will need to name your {myslug}to something different like {myslug2}, otherwise Laravel will not run all of the routes.
注意：如果您在路由文件中使用此路由的副本，但要搜索不同的子字符串，则需要将其命名{myslug}为不同的名称，例如{myslug2}，否则 Laravel 将不会运行所有路由。
