C# DataContractJsonSerializer 的反序列化问题
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Deserialization problem with DataContractJsonSerializer
提问by bbrown
I've got the following piece of JSON:
我有以下一段 JSON：
[{
"name": "numToRetrieve",
"value": "3",
"label": "Number of items to retrieve:",
"items": {
"1": "1",
"3": "3",
"5": "5"
},
"rules": {
"range": "1-2"
}
},
{
"name": "showFoo",
"value": "on",
"label": "Show foo?"
},
{
"name": "title",
"value": "Foo",
"label": "Foo:"
}]
All in one line version (suitable for a string literal):
全在一行版本（适用于字符串文字）：
[{\"name\":\"numToRetrieve\",\"value\":\"3\",\"label\":\"Number of items to retrieve:\",\"items\":{\"1\":\"1\",\"3\":\"3\",\"5\":\"5\"},\"rules\":{\"range\":\"1-2\"}},{\"name\":\"showFoo\",\"value\":\"on\",\"label\":\"Show foo?\"},{\"name\":\"title\",\"value\":\"Foo\",\"label\":\"Foo:\"}]
In the above example, name, value, and labelare required but itemsand rulesare optional.
在上面的示例中name，value、 和label是必需的，但items和rules是可选的。
Here's the class I'm trying to deserialize into:
这是我试图反序列化的类：
using System.Collections;
using System.Collections.Generic;
using System.Runtime.Serialization;
namespace foofoo
{
[DataContract]
public sealed class FooDef
{
[DataMember(Name = "name", IsRequired = true)]
public string Name { get; set; }
[DataMember(Name = "value", IsRequired = true)]
public string Value { get; set; }
[DataMember(Name = "label", IsRequired = true)]
public string Label { get; set; }
[DataMember(Name = "items", IsRequired = false)]
public Dictionary<string, string> Items { get; set; }
[DataMember(Name = "rules", IsRequired = false)]
public Dictionary<string, string> Rules { get; set; }
}
}
Here's the code I use to deserialize:
这是我用来反序列化的代码：
var json = new DataContractJsonSerializer(typeof(List<FooDef>));
var bar = "[{\"name\":\"numToRetrieve\",\"value\":\"3\",\"label\":\"Number of items to retrieve:\",\"items\":{\"1\":\"1\",\"3\":\"3\",\"5\":\"5\"},\"rules\":{\"range\":\"1-2\"}},{\"name\":\"showFoo\",\"value\":\"on\",\"label\":\"Show foo?\"},{\"name\":\"title\",\"value\":\"Foo\",\"label\":\"Foo:\"}]";
var stream = new MemoryStream(Encoding.UTF8.GetBytes(bar));
var foo = json.ReadObject(stream);
stream.Close();
Everything goes reasonably well except that itemsand rulesare empty for the first FooDefpass. I have tried everything under the sun to try and get them populated: custom classes, NameValueCollection, KeyValuePair<string, string>, Listof both of the latter, and every other collection that seemed to apply. [EDIT: I forgot to try Hashtable, which seemed like an obvious candidate. Didn't work.]
一切进展相当不错，除了items和rules是空的第一个FooDef通行证。我曾尝试一切在阳光下，试图让他们填充：自定义类，NameValueCollection，KeyValuePair<string, string>，List无论是后者，和所有其他的集合，似乎适用的。[编辑：我忘了尝试Hashtable，这似乎是一个明显的候选人。没有用。]
The problem, as I see it, is that the key piece under itemsand rulesis open-ended. That is, it's not always going to be called rangeor 3. Any advice or ideas?
这个问题，在我看来，是在关键件items和rules是开放式的。也就是说，它并不总是被称为rangeor 3。有什么建议或想法吗？
采纳答案by Darin Dimitrov
IMHO there is no way to deserialize the JSON string you provided into a .NET class using DataContractJsonSerializer.
恕我直言，无法使用 DataContractJsonSerializer 将您提供的 JSON 字符串反序列化为 .NET 类。
The problem comes from the way DataContractJsonSerializerserializes dictionaries. You could use an alternative serializer such as Json.NET(which I strongly recommend) or JavaScriptSerializer(I think it was deprecated in favor of DataContractJsonSerializer but it will work for your scenario).
问题来自DataContractJsonSerializer序列化字典的方式。您可以使用替代序列化程序，例如Json.NET（我强烈推荐）或JavaScriptSerializer（我认为它已被弃用，以支持 DataContractJsonSerializer，但它适用于您的场景）。
Documentation: Serializing Collections - Json.NET
回答by Sean Kelly
http://social.msdn.microsoft.com/Forums/en-US/wcf/thread/071f73bb-e141-4a68-ae61-05635382934f
http://social.msdn.microsoft.com/Forums/en-US/wcf/thread/071f73bb-e141-4a68-ae61-05635382934f
Check this article out - it solved my problem almost perfectly. I had to change their object[] Type to a string, but i'm only using strings:string type Key/Value pairs, so no problems there.
看看这篇文章 - 它几乎完美地解决了我的问题。我不得不将他们的 object[] Type 更改为字符串，但我只使用 strings:string type Key/Value 对，所以没有问题。
