bash 执行包含来自 shell 变量的引号的命令
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Execute command containing quotes from shell variable
提问by Markus Kreusch
I'm currently having problems to execute a command from a shell variable.
我目前在从 shell 变量执行命令时遇到问题。
In general the following works as expected:
一般来说，以下工作按预期工作：
COMMAND="echo A"
echo $COMMAND
$COMMAND
produces:
产生：
echo A
A
But if I do
但如果我这样做
COMMAND="su aUser -s /bin/bash -c 'echo A'"
echo $COMMAND
$COMMAND
I get
我得到
su aUser -s /bin/bash -c 'echo A'
Password:
A': -c: line 0: unexpected EOF while looking for matching `''
A': -c: line 1: syntax error: unexpected end of file
If I enter the line
如果我输入该行
su aUser -s /bin/bash -c 'echo A'
directly it works as expected.
直接它按预期工作。
It seems my assumption that $COMMAND is equal to entering the content as command directly is wrong.
似乎我的假设 $COMMAND 等于直接输入内容作为命令是错误的。
Questions
问题
1) Does anyone know how I can run the command from a variable?
1）有谁知道我如何从变量运行命令？
2) What exactly is the difference between
2）到底有什么区别
COMMAND="command"
$COMMAND
and
和
command
?
?
回答by glenn Hymanman
Arrays are useful to keep your parameters whole:
数组对于保持参数完整很有用：
command=(su aUser -s /bin/bash -c 'echo A')
and invoke it exactly like this:
并完全像这样调用它：
"${command[@]}"
回答by Igor Chubin
You need eval.
你需要eval.
$ eval $VARIABLE
