在 PostgreSQL 中将行转换为列
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Convert rows to column in PostgreSQL
提问by nagi
I want to convert rows to column in PostgreSQL.I want all variables against their respective id.but its not working.
我想在 PostgreSQL 中将行转换为列。我希望所有变量都针对它们各自的 id。但它不起作用。
Expected Output:
预期输出：
myvar desc fname lname sdate edate id
title1 desc1 cina jhon 1483920000000 1484524800000 14
title2 desc2 jhon lname2 1483920000000 1483910000000 16
title3 desc3 diesel zier 1483920000000 1484524800000 17
SELECT * FROM crosstab(
'SELECT name, value, id FROM test ORDER BY id') AS (
"myVar" text, "desc" text, "fname" text, "lname" text,"sdate" text,"edate" text, "value" text ,"containerid" bigint);
Error: ERROR: invalid return type SQL state: 42601 Detail: SQL rowid datatype does not match return rowid datatype.
错误：错误：无效的返回类型 SQL 状态：42601 详细信息：SQL rowid 数据类型与返回 rowid 数据类型不匹配。
回答by McNets
Maybe this can helps.
也许这会有所帮助。
ORDER BY 1,2is required here.
ORDER BY 1,2这里需要。
select *
from crosstab (
'select id, name, value
from tt1
order by 1,2')
AS (row_name int, col1 text, col2 text, col3 text, col4 text);
+----------+-------+--------+--------+--------+
| row_name | col1 | col2 | col3 | col4 |
+----------+-------+--------+--------+--------+
| 14 | desc1 | chen | john | title1 |
+----------+-------+--------+--------+--------+
| 15 | desc2 | fname2 | lname2 | title2 |
+----------+-------+--------+--------+--------+
| 16 | desc4 | deiser | ziel | title3 |
+----------+-------+--------+--------+--------+
In fact, columns should be named as: col1, col2, col3, col4, ...
实际上，列应该命名为：col1、col2、col3、col4、...
Check it here: http://rextester.com/MFWAW58518
在这里查看：http: //rextester.com/MFWAW58518
