Python：类型错误：__init__() 正好有 2 个参数（给定 1 个）
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Python: TypeError: __init__() takes exactly 2 arguments (1 given)
提问by mee
I know this question has been asked several times, but none have managed to provide me with a solution to my issue. I read these:
我知道这个问题已经被问过好几次了，但是没有一个能够为我提供解决我的问题的方法。我读了这些：
__init__() takes exactly 2 arguments (1 given)?
__init__() 正好接受 2 个参数（给定 1 个）？
class __init__() takes exactly 2 arguments (1 given)
类 __init__() 正好接受 2 个参数（给定 1 个）
All I am trying to do is create two classes for a "survival game" much like a very crappy version of minecraft. Bellow is the full code for the two classes:
我想要做的就是为“生存游戏”创建两个类，就像一个非常糟糕的我的世界版本。Bellow 是这两个类的完整代码：
class Player:
'''
Actions directly relating to the player/character.
'''
def __init__(self, name):
self.name = name
self.health = 10
self.shelter = False
def eat(self, food):
self.food = Food
if (food == 'apple'):
Food().apple()
elif (food == 'pork'):
Food().pork()
elif (food == 'beef'):
Food().beef()
elif (food == 'stew'):
Food().stew()
class Food:
'''
Available foods and their properties.
'''
player = Player()
def __init__(self):
useless = 1
Amount.apple = 0
Amount.pork = 0
Amount.beef = 0
Amount.stew = 0
class Amount:
def apple(self):
player.health += 10
def pork(self):
player.health += 20
def beef(self):
player.health += 30
def stew(self):
player.health += 25
And now for the full error:
现在是完整的错误：
Traceback (most recent call last):
File "/home/promitheas/Desktop/programming/python/pygame/Survive/survive_classe s.py", line 26, in <module>
class Food:
File "/home/promitheas/Desktop/programming/python/pygame/Survive/survive_classe s.py", line 30, in Food
player = Player()
TypeError: __init__() takes exactly 2 arguments (1 given)
I just want to make the classes work.
我只想让课程发挥作用。
采纳答案by Jerry
The code you used is as follows:
您使用的代码如下：
player = Player()
This is an issue since the __init__must be supplied by one parameter called nameaccording to your code. Therefore, to solve your issue, just supply a name to the Player constructor and you are all set:
这是一个问题，因为__init__必须由name根据您的代码调用的一个参数提供。因此，要解决您的问题，只需为 Player 构造函数提供一个名称即可：
player = Player('sdfasf')
回答by Bhargav Rao
The problem is that the Class Player's __init__function accepts a nameargument while you are initializing the Class instance. The first argument, selfis automatically handled when you create a class instance. So you have to change
问题是 ClassPlayer的__init__函数name在您初始化 Class 实例时接受一个参数。第一个参数self在您创建类实例时自动处理。所以你必须改变
player = Player()
to
到
player = Player('somename')
to get the program up and running.
启动并运行程序。
回答by MattDMo
__init__()is the function called when the class is instantiated. So, any arguments required by __init__need to be passed when creating an instance. So, instead of
__init__()是类被实例化时调用的函数。因此，__init__创建实例时需要传递所需的任何参数。所以，而不是
player = Player()
use
用
player = Player("George")
The first argument is the implicit self, which doesn't need to be included when instantiating. name, however, is required. You were getting the error because you weren't including it.
第一个参数是隐式self，实例化时不需要包含它。name，然而，是必需的。您收到错误是因为您没有包含它。
回答by Tenzin
Your code know expects that you input something in __init__which you don't.
I have made a simple example below that does give you an idea where the error __init__() takes exactly 2 arguments (1 given)is coming from.
What I did is I made a definition where I give input to useless.
And I am calling that definition from __init__.
您的代码知道期望您输入一些__init__您没有输入的内容。
我在下面做了一个简单的例子，它确实让你知道错误__init__() takes exactly 2 arguments (1 given)来自哪里。
我所做的是我做了一个定义，在那里我给useless.
我从__init__.
Example code:
示例代码：
class HelloWorld():
def __init__(self):
self.useThis(1)
def useThis(self, useless):
self.useless = useless
print(useless)
# Run class
HelloWorld()
If you have a definition like def exampleOne(self)it doesn't expect any input. It just looks a t itself.
But def exampleTwo(self, hello, world)expects two inputs.
So to call these two you need:
如果您有这样的定义，def exampleOne(self)则不需要任何输入。它只是看着自己。
但def exampleTwo(self, hello, world)需要两个输入。
所以要调用这两个你需要：
self.exampleOne()
self.exampleTwo('input1', 'input2')
