php 从字符串中删除第一个和最后一个字符
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Remove first and last char from string
提问by user248488
I have this:
我有这个：
$dataList = "*one*two*three*";
$list = explode("*", $dataList);
echo"<pre>";print_r($list);echo"</pre>";
which outputs:
输出：
> Array (
> [0] =>
> [1] => one
> [2] => two
> [3] => three
> [4] => )
How do I strip the fist and last * in the string before exploding?
如何在爆炸前去除字符串中的拳头和最后一个 *？
回答by NikiC
回答by Bojoer
Some other possibilities:
其他一些可能性：
Using substr:
使用 substr：
$dataList = substr($dataList, 1, -1);
You can also choose to not remove the * from the string but rather remove the empty array values which will always be the first and last element. Using array functions array_pop() and array_shift():
您还可以选择不从字符串中删除 *，而是删除始终是第一个和最后一个元素的空数组值。使用数组函数 array_pop() 和 array_shift()：
$arrData = array_pop(array_shift($arrData));
回答by reko_t
trim($dataList, "*")
回答by Syed Sxxis
$string = substr($dataList, 1, -1);
$string = substr($dataList, 1, -1);
Remove the first and the last character of the string in php
去掉php中字符串的第一个和最后一个字符
回答by Akbar Adeeb
echo trim($dataList,"*");
hope this solve your problem
希望这能解决你的问题
