PHP 错误：试图获取非对象的属性

PHP Error: Trying to get property of non-object

提问by Tom

I am working in CodeIgniter framework and I have tried to apply all the other solutions I found on stack but I could not make it work so here is my problem... I am trying to retrieve a record from MySQL database table called 'questions' based on uri segment. Then I am trying to display this record in a view. As far as I can tell, the uri segment is passed along everywhere it needs to be, and record is retrieved from database. The problem comes up when I am trying to access the data from the controller, in my view. Error I am getting for each echo in my loop in 'view_thread_view' is

我在 CodeIgniter 框架中工作，我试图应用我在堆栈上找到的所有其他解决方案，但我无法使其工作，所以这是我的问题......我正在尝试从名为“问题”的 MySQL 数据库表中检索记录基于uri段。然后我试图在视图中显示这条记录。据我所知，uri 段被传递到它需要的任何地方，并从数据库中检索记录。在我看来，当我尝试从控制器访问数据时，问题就出现了。我在“view_thread_view”的循环中为每个回声得到的错误是

A PHP Error was encountered

Severity: Notice

Message: Trying to get property of non-object

Filename: views/view_thread_view.php

遇到 PHP 错误

严重性：注意

消息：试图获取非对象的属性

文件名：views/view_thread_view.php

Any solutions would be greatly appreciated.

任何解决方案将不胜感激。

Here is my code:

这是我的代码：

Controller thread

控制器线程

function view_thread()
    {
        $quest = $this->uri->segment(3);
        echo $quest;// for checking if uri segment is passed

        if($query = $this->data_model->get_thread($quest))
        {
            $data['records'] = $query;      
        }

        $this->load->view('view_thread_view', $data);

Model data_model

模型数据_模型

public function get_thread($quest)
   {
    if($q = $this->db->get_where('questions' , 'qid' , $quest));
    {
      return $q;
    }
   }

View view_thread_view

查看 view_thread_view

<div title="question_view">
    <h1>Question View<h1>
        <?php foreach($records as $data) : ?>
        <div>
            <h2>Title</h2>
            <?php 
            echo $data->title;
            ?>
        </div>
        <div>
            <h2>Question</h2>
            <?php
            echo $data->contents
            ?>
        </div>
        <div>
            <h2>Tags</h2>
            <?php
            echo $data->tags
            ?>
        </div>
        <div>
            Thread owner
            <?php
            echo $records->uname
            ?>
        </div>
    <?php endforeach; ?>
</div>

EDIT: QUESTION ANSWERED

编辑：问题已回答

Thanks to Girish Jangid fixed the problem this is the working code:

感谢 Girish Jangid 解决了这个问题，这是工作代码：

Controller

控制器

function view_thread()
    {
        $quest = $this->uri->segment(3);
        echo $quest;// for checking if uri segment is passed
        //$data = array();
        if($query = $this->data_model->get_thread($quest))
        {
            $data['records'] = $query;      
        }

        $this->load->view('view_thread_view', $data);
    }

Model

模型

public function get_thread($quest)
   {
    if($q = $this->db->get_where('questions' , array('qid' => $quest)));
    {
      return $q;
    }

   }

View

看法

<div title="question_view">
    <h1>Question View<h1>

        <?php foreach($records->result() as $data) : ?>
        <div>
            <h2>Title</h2>
            <?php 
            echo $data->title;
            ?>
        </div>
        <div>
            <h2>Question</h2>
            <?php
            echo $data->contents
            ?>
        </div>
        <div>
            <h2>Tags</h2>
            <?php
            echo $data->tags
            ?>
        </div>
        <div>
            Thread owner
            <?php
            echo $data->uname
            ?>
        </div>
    <?php endforeach; ?>

</div>
</div>

回答by Girish

You should user db function to fetch results, please use CodeIgniter db Query Results functions, like this

你应该使用 db 函数来获取结果，请使用 CodeIgniter db Query Results 函数，像这样

 if($records->num_rows() > 0){
      foreach($records->result() as $data){
        if(isset($data->title)) echo $data->title;
      }
    }

For more detail please read CodeIgniter Query Result function Query Results

更多细节请阅读 CodeIgniter 查询结果函数 查询结果

Try this code

试试这个代码

<div title="question_view">
    <h1>Question View<h1>
        <?php if($records->num_rows() > 0) { ?>  
        <?php foreach($records->result() as $data) : ?>
        <div>
            <h2>Title</h2>
            <?php 
            echo $data->title;
            ?>
        </div>
        <div>
            <h2>Question</h2>
            <?php
            echo $data->contents
            ?>
        </div>
        <div>
            <h2>Tags</h2>
            <?php
            echo $data->tags
            ?>
        </div>
        <div>
            Thread owner
            <?php
            echo $records->uname
            ?>
        </div>
    <?php endforeach; ?>
    <?php } ?>
</div>

回答by Jessica

$recordsis an array, not an object, therefore you cannot do $records->uname. You probably meant $datathere too.

$records是一个数组，而不是一个对象，因此你不能做$records->uname。你可能$data也是那个意思。

Edit: On second look, it appears $datais an array as well! Arrays are accessed via ['key']not ->key

编辑：再看，它似乎$data也是一个数组！数组是通过['key']not访问的->key

Also, your code is way over complicated.

此外，您的代码过于复杂。

<?php 
foreach($records as $data){
   $string = <<<STR
   <div>
      <h2>Title</h2>
      {$data['title']}
    </div>
    ...etc
STR;
    echo $string;
}

http://www.php.net/manual/en/language.types.string.php

http://www.php.net/manual/en/language.types.string.php