Java Maven中的依赖jar文件列表
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List of dependency jar files in Maven
提问by Sindri Traustason
Using Maven 2, is there a way I can list out the jar dependencies as just the file names?
使用 Maven 2，有没有一种方法可以将 jar 依赖项作为文件名列出？
mvn dependency:build-classpath
can list the jar files, but that will include the full path to their location in my local repository. What I need is essentially just a list of the file names (or the file names that the copy-dependencies goal copied).
可以列出 jar 文件，但这将包括它们在我的本地存储库中的位置的完整路径。我需要的本质上只是一个文件名列表（或复制依赖项目标复制的文件名）。
So the list I need would be something like
所以我需要的清单类似于
activation-1.1.jar,antlr-2.7.6.jar,aopalliance-1.0.jar etc...
ideally as a maven property, but I guess, a file such as build-classpath can generate will do.
理想情况下作为 maven 属性，但我想，可以生成诸如 build-classpath 之类的文件就可以了。
What I am trying to achieve is writing a Bundle-ClassPathto an otherwise manually maintained MANIFEST.MF file for a OSGi bundle. (You shouldn't need to understand this bit to answer the question.)
我想要实现的是Bundle-ClassPath为 OSGi 包写入一个手动维护的 MANIFEST.MF 文件。（你不应该需要理解这一点来回答这个问题。）
To clarify: The question is notabout how to write manifest headers into the MANIFEST.MF file in a jar (that is easily googleble). I am asking about how to get the data I want to write, namely the list shown above.
澄清一下：问题不在于如何将清单标头写入 jar 中的 MANIFEST.MF 文件（这很容易用 googleble 搜索）。我在问如何获取我要写入的数据，即上面显示的列表。
回答by Davide Gualano
Maven can build the classpath in your manifest automatically: http://maven.apache.org/guides/mini/guide-manifest.html
Maven 可以自动在您的清单中构建类路径：http: //maven.apache.org/guides/mini/guide-manifest.html
It's a configuration of the Maven archive plugin.
它是 Maven 归档插件的配置。
回答by sblundy
Have you looked at the Apache Felixproject? It has a whole mess of plugins, including a bundle pluginthat should do what you want.
你看过Apache Felix项目吗？它有一大堆插件，包括一个可以做你想做的插件。
Also, have you tried the <addClasspath>tag with <manifestFile>? That should have the desired effect of merging the classpath into your manifest.
另外，你有没有试过<addClasspath>标签<manifestFile>？这应该具有将类路径合并到清单中的预期效果。
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
...
<configuration>
<archive>
<addClasspath>true</addClasspath>
<manifestFile>src/main/resources/META-INF/MANIFEST.MF</manifestFile>
</archive>
</configuration>
...
</plugin>
回答by Gabe Mc
As best as I can tell, you can't get exactly that output, with the commas and no spaces. Both via the command line and via the pom.xml file, the maven-dependency-plugin or the CLI freaks out if you specify spaces or the '' (empty string) as a substitute with either pathSeparatoror fileSeparator. So, you may be forced to reach something of a compromise. You can
尽我所知，您无法获得准确的输出，其中包含逗号且没有空格。无论是通过命令行还是通过 pom.xml 文件，如果您指定空格或 ''（空字符串）作为pathSeparator或的替代品，maven-dependency-plugin 或 CLI 都会出问题fileSeparator。因此，您可能会被迫达成某种妥协。你可以
mvn dependency:build-classpath -Dmdep.pathSeparator=":" -Dmdep.prefix='' -Dmdep.fileSeparator=":" -Dmdep.outputFile=classpath
However, that should get you a full list, separated by '::'instead of just ',', but it works. If you run:
但是，这应该会为您提供一个完整的列表，由 分隔，'::'而不仅仅是','，但它有效。如果你运行：
mvn dependency:build-classpath -Dmdep.pathSeparator="@REPLACEWITHCOMMA" -Dmdep.prefix='' -Dmdep.fileSeparator="@" -Dmdep.outputFile=classpath
andattach this to the generate-resourcesphase andfilter that resource later by setting the correct property in the process-resourcesphase of the lifecycle, you shouldbe able to get just the comma.
并将其附加到generate-resources阶段并稍后通过process-resources在生命周期的阶段设置正确的属性来过滤该资源，您应该能够获得逗号。
You can see the full list of options at: http://maven.apache.org/plugins/maven-dependency-plugin/build-classpath-mojo.html
您可以在以下位置查看完整的选项列表： http://maven.apache.org/plugins/maven-dependency-plugin/build-classpath-mojo.html
回答by Kevin Wright
I may be missing something here, but as you've already used copy-dependencies it sounds like what you're really after is just a list of files in a specified directory.
我可能在这里遗漏了一些东西，但是由于您已经使用了复制依赖项，因此听起来您真正想要的只是指定目录中的文件列表。
Ant can do this for you without any problems, as can a shell script.
Ant 可以毫无问题地为您执行此操作，shell 脚本也可以。
回答by Anis
This command will generate the dependencies tree of your maven project:
此命令将生成 Maven 项目的依赖关系树：
$ mvn dependency:tree
I am sure that you will like the result :-)
我相信你会喜欢这个结果:-)
回答by Andrew
To add a notch to the existing answers, the current maven-dependency-plugin allows saving the classpath to a property with the outputPropertyparameter.
要为现有答案添加一个缺口，当前的 maven-dependency-plugin 允许将类路径保存到带有outputProperty参数的属性。
回答by naXa
Here's the command you're asking for
这是你要求的命令
$ mvn dependency:tree
For large projects it can output a lot of text. I assume that you want to check that dependency tree contains a certain dependency, so you don't need a full list.
对于大型项目，它可以输出大量文本。我假设您想检查依赖树是否包含某个依赖项，因此您不需要完整列表。
Here's how you can filter output on Windows:
以下是在 Windows 上过滤输出的方法：
$ mvn dependency:tree | findstr javax.persistence
And here's how you can do it on Linux:
以下是在 Linux 上执行此操作的方法：
$ mvn dependency:tree | grep javax.persistence
Maven way to filter the dependency tree(works in Windows cmd, MacOS and Linux shell):
Maven过滤依赖树的方法（适用于 Windows cmd、MacOS 和 Linux shell）：
$ mvn dependency:tree -Dincludes=javax.persistence:*
Maven way (Windows PowerShell):
Maven 方式（Windows PowerShell）：
$ mvn dependency:tree '-Dincludes=javax.persistence:*'
回答by kisna
Actually, for just the final list of jars, simply use
实际上，对于罐子的最终列表，只需使用
mvn dependency:list
Which is lot more simple than dependency:tree which is an overkill to simply get the final list as it shows detailed transitive tree and conflict resolution (with verbose).
这比dependency:tree简单得多，因为它显示了详细的传递树和冲突解决方案（详细说明），所以简单地获取最终列表是一种矫枉过正。
回答by Matthieu
Here is an awk script to pipe mvn dependency:list:
这是一个用于管道的 awk 脚本mvn dependency:list：
mvn dependency:list | awk -f mvnfmt.awk
You can | sortif you want to sort by name, or | tr '\n' ':'to format it to a classpath.
你可以| sort，如果你想以按名称排序，或| tr '\n' ':'将其格式化到类路径。
mvnfmt.awkis:
mvnfmt.awk是：
BEGIN {
found = 0
}
/The following files have been resolved/ {
found = 1
next
}
/^\[INFO\] $/ {
print "Empty " found
if (found != 0) found = 0
}
{
if (!found) next
n = split(##代码##, a, " ")
if (n != 2) {
found = 0
next
}
split(a[2], a, ":")
print a[2] "-" a[4] "." a[3]
}
