Python AttributeError: 对象没有属性“拆分”
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AttributeError: object has no attribute 'split'
提问by user3849475
There is an error,when I try to split
出现错误，当我尝试拆分时
l =[u'this is friday', u'holiday begin']
split_l =l.split()
print(split_l)
The error is:
错误是：
Traceback (most recent call last):
File "C:\Users\spotify_track2.py", line 19, in <module>
split_l =l.split()
AttributeError: 'list' object has no attribute 'split'
So I don't have idea to deal with this kind of error.
所以我不知道处理这种错误。
采纳答案by Bhargav Rao
Firstly, do not name your variable as list
首先，不要将您的变量命名为 list
Secondly listdoes not have the function splitIt is strwhich has it.
其次list是没有功能split它是str有它的。
Check the documentation for str.split
检查文档 str.split
Return a list of the words in the string, using sep as the delimiter string
返回字符串中单词的列表，使用 sep 作为分隔符字符串
(emphasis mine)
（强调我的）
So you need to do
所以你需要做
l =[u'this is friday', u'holiday begin']
split_list =[i.split() for i in l]
print(split_list)
Which would print
哪个会打印
[[u'this', u'is', u'friday'], [u'holiday', u'begin']]
Post Comment edit
发表评论编辑
To get what you expected you can try
为了得到你所期望的，你可以尝试
>>> l =[u'this is friday', u'holiday begin']
>>> " ".join(l).split(" ")
[u'this', u'is', u'friday', u'holiday', u'begin']
or as mentioned below
或如下所述
>>> [j for i in split_list for j in i]
[u'this', u'is', u'friday', u'holiday', u'begin']
