Python matplotlib 图例的标题
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Title for matplotlib legend
提问by Brandon Molyneaux
I know it seems fairly redundant to have a title for a legend, but is it possible using matplotlib?
我知道为图例设置标题似乎相当多余，但是是否可以使用 matplotlib？
Here's a snippet of the code I have:
这是我拥有的代码片段：
import matplotlib.patches as mpatches
import matplotlib.pyplot as plt
one = mpatches.Patch(facecolor='#f3f300', label='label1', linewidth = 0.5, edgecolor = 'black')
two = mpatches.Patch(facecolor='#ff9700', label = 'label2', linewidth = 0.5, edgecolor = 'black')
three = mpatches.Patch(facecolor='#ff0000', label = 'label3', linewidth = 0.5, edgecolor = 'black')
legend = plt.legend(handles=[one, two, three], loc = 4, fontsize = 'small', fancybox = True)
frame = legend.get_frame() #sets up for color, edge, and transparency
frame.set_facecolor('#b4aeae') #color of legend
frame.set_edgecolor('black') #edge color of legend
frame.set_alpha(1) #deals with transparency
plt.show()
I would want the title of the legend above label1. For reference, this is the output:
我想要标签1上方的图例标题。作为参考，这是输出：
回答by Alper F?rat Kaya
Add the titleparameter to the this line:
将title参数添加到此行：
legend = plt.legend(handles=[one, two, three], title="title",
loc=4, fontsize='small', fancybox=True)
See also the official docs for the legendconstructor.
另请参阅构造函数的官方文档legend。
回答by ErnestScribbler
Just to add to the accepted answer that this also works with an Axes object.
只是为了添加到已接受的答案中，这也适用于 Axes 对象。
fig, ax = plt.subplots()
ax.plot([0, 1, 2], [0, 1, 4], label='some_label') # Or however the Axes was created.
ax.legend(title='This is My Legend Title')
