vba 这是用于匹配 Excel 公式中的任何单元格引用的 RegEx 吗?
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Is this the RegEx for matching any cell reference in an Excel formula?
提问by Kuyenda
I have been trying to create a regular expressions pattern that matches any reference in any Excel formula, including absolute, relative, and external references. I need to return the entire reference, including the worksheet and workbook name.
我一直在尝试创建一个正则表达式模式,以匹配任何 Excel 公式中的任何引用,包括绝对引用、相对引用和外部引用。我需要返回整个引用,包括工作表和工作簿名称。
I haven't been able to find exhaustive documentation about Excel A1-notation, but with a lot of testing I have determined the following:
我无法找到有关 Excel A1 表示法的详尽文档,但通过大量测试,我确定了以下内容:
- Formulas are preceded with an equal sign "="
- Strings within formulas are enclosed in double quotes and need to be removed before looking for real references, otherwise
=A1&"A1"
would break regex - Worksheet names can be up to 31 characters long, excluding \ / ? * [ ] :
- Worksheet names in external references must be succeeded with bang
=Sheet1!A1
- Workbook names in external references must be enclosed in square brackets
=[Book1.xlsx]Sheet1!A1
- Workbook paths, which Excel adds if a reference is to a range in a closed workbook, are always enclosed in single quotes and to the left of the brackets for the workbook name
'C:\[Book1.xlsx]Sheet1'!A1
- Some characters (non-breaking space, for example) cause Excel to enclose the workbook and worksheet name in an external reference in single quotes, but I don't know specifically which characters
='[Book 1.xlsx]Sheet 1'!A1
- Even if R1C1-notation is enabled,
Range.Formula
still returns references in A1-notation.Range.FormulaR1C1
returns references in R1C1 notation. - 3D reference style allows a range of sheet names on one workbook
=SUM([Book5]Sheet1:Sheet3!A1)
- Named ranges can be specified in formulas:
- The first character of a name must be a letter, an underscore character (_), or a backslash (\). Remaining characters in the name can be letters, numbers, periods, and underscore characters.
- You cannot use the uppercase and lowercase characters "C", "c", "R", or "r" as a defined name, because they are all used as a shorthand for selecting a row or column for the currently selected cell when you enter them in a Name or Go To text box.
- Names cannot be the same as a cell reference, such as Z$100 or R1C1.
- Spaces are not allowed as part of a name.
- A name can be up to 255 characters in length.
- Names can contain uppercase and lowercase letters. Excel does not distinguish between uppercase and lowercase characters in names.
- 公式以等号“=”开头
- 公式中的字符串用双引号括起来,在查找真正的引用之前需要将其删除,否则
=A1&"A1"
会破坏正则表达式 - 工作表名称最长可达 31 个字符,不包括 \ / ? * [ ] :
- 外部引用中的工作表名称必须以 bang 成功
=Sheet1!A1
- 外部引用中的工作簿名称必须用方括号括起来
=[Book1.xlsx]Sheet1!A1
- 工作簿路径(如果引用是对封闭工作簿中的区域的引用,则 Excel 添加)始终用单引号括起来,并位于工作簿名称的括号左侧
'C:\[Book1.xlsx]Sheet1'!A1
- 某些字符(例如,不间断空格)会导致 Excel 将工作簿和工作表名称用单引号括在外部引用中,但我不知道具体是哪些字符
='[Book 1.xlsx]Sheet 1'!A1
- 即使启用了 R1C1 表示法,
Range.Formula
仍然以 A1 表示法返回引用。Range.FormulaR1C1
以 R1C1 表示法返回引用。 - 3D 参考样式允许在一个工作簿上使用一系列工作表名称
=SUM([Book5]Sheet1:Sheet3!A1)
- 命名范围可以在公式中指定:
- 名称的第一个字符必须是字母、下划线字符 (_) 或反斜杠 (\)。名称中的剩余字符可以是字母、数字、句点和下划线字符。
- 不能使用大写和小写字符“C”、“c”、“R”或“r”作为定义的名称,因为它们都用作为当前选定的单元格选择行或列的简写在名称或转到文本框中输入它们。
- 名称不能与单元格引用相同,例如 Z$100 或 R1C1。
- 不允许将空格作为名称的一部分。
- 名称最长可达 255 个字符。
- 名称可以包含大写和小写字母。Excel 不区分名称中的大写和小写字符。
Here is what I came up with wrapped in a VBA procedure for testing. I updated the code to handle names as well:
这是我想出的包含在 VBA 程序中进行测试的内容。我也更新了代码来处理名称:
Sub ReturnFormulaReferences()
Dim objRegExp As New VBScript_RegExp_55.RegExp
Dim objCell As Range
Dim objStringMatches As Object
Dim objReferenceMatches As Object
Dim objMatch As Object
Dim intReferenceCount As Integer
Dim intIndex As Integer
Dim booIsReference As Boolean
Dim objName As Name
Dim booNameFound As Boolean
With objRegExp
.MultiLine = True
.Global = True
.IgnoreCase = True
End With
For Each objCell In Selection.Cells
If Left(objCell.Formula, 1) = "=" Then
objRegExp.Pattern = "\"".*\"""
Set objStringMatches = objRegExp.Execute(objCell.Formula)
objRegExp.Pattern = "(\'.*(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\!)?" _
& "($?[a-z]{1,3}$?[0-9]{1,7}(\:$?[a-z]{1,3}$?[0-9]{1,7})?" _
& "|$[a-z]{1,3}\:$[a-z]{1,3}" _
& "|[a-z]{1,3}\:[a-z]{1,3}" _
& "|$[0-9]{1,7}\:$[0-9]{1,7}" _
& "|[0-9]{1,7}\:[0-9]{1,7}" _
& "|[a-z_\][a-z0-9_\.]{0,254})"
Set objReferenceMatches = objRegExp.Execute(objCell.Formula)
intReferenceCount = 0
For Each objMatch In objReferenceMatches
intReferenceCount = intReferenceCount + 1
Next
Debug.Print objCell.Formula
For intIndex = intReferenceCount - 1 To 0 Step -1
booIsReference = True
For Each objMatch In objStringMatches
If objReferenceMatches(intIndex).FirstIndex > objMatch.FirstIndex _
And objReferenceMatches(intIndex).FirstIndex < objMatch.FirstIndex + objMatch.Length Then
booIsReference = False
Exit For
End If
Next
If booIsReference Then
objRegExp.Pattern = "(\'.*(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\!)?" _
& "($?[a-z]{1,3}$?[0-9]{1,7}(\:$?[a-z]{1,3}$?[0-9]{1,7})?" _
& "|$[a-z]{1,3}\:$[a-z]{1,3}" _
& "|[a-z]{1,3}\:[a-z]{1,3}" _
& "|$[0-9]{1,7}\:$[0-9]{1,7}" _
& "|[0-9]{1,7}\:[0-9]{1,7})"
If Not objRegExp.Test(objReferenceMatches(intIndex).Value) Then 'reference is not A1
objRegExp.Pattern = "^(\'.*(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\!)" _
& "[a-z_\][a-z0-9_\.]{0,254}$"
If Not objRegExp.Test(objReferenceMatches(intIndex).Value) Then 'name is not external
booNameFound = False
For Each objName In objCell.Worksheet.Parent.Names
If objReferenceMatches(intIndex).Value = objName.Name Then
booNameFound = True
Exit For
End If
Next
If Not booNameFound Then
objRegExp.Pattern = "^(\'.*(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\!)"
For Each objName In objCell.Worksheet.Names
If objReferenceMatches(intIndex).Value = objRegExp.Replace(objName.Name, "") Then
booNameFound = True
Exit For
End If
Next
End If
booIsReference = booNameFound
End If
End If
End If
If booIsReference Then
Debug.Print " " & objReferenceMatches(intIndex).Value _
& " (" & objReferenceMatches(intIndex).FirstIndex & ", " _
& objReferenceMatches(intIndex).Length & ")"
End If
Next intIndex
Debug.Print
End If
Next
Set objRegExp = Nothing
Set objStringMatches = Nothing
Set objReferenceMatches = Nothing
Set objMatch = Nothing
Set objCell = Nothing
Set objName = Nothing
End Sub
Can anyone break or improve this? Without exhaustive documentation on Excel's formula syntax it is difficult to know if this is correct.
任何人都可以打破或改善这一点吗?如果没有关于 Excel 公式语法的详尽文档,很难知道这是否正确。
Thanks!
谢谢!
采纳答案by Kuyenda
jtolle steered me in the right direction. As far as I can tell, this is what I was trying to do. I've been testing and it seems to work.
jtolle 将我引向正确的方向。据我所知,这就是我想要做的。我一直在测试,它似乎工作。
stringOriginFormula = rangeOrigin.Formula
rangeOrigin.Cut rangeDestination
rangeOrigin.Formula = stringOriginFormula
Thanks jtolle!
谢谢jtolle!
回答by Mark E.
I'm a few years late here, but I was looking for something similar and so dug into this. The main pattern you use is this:
我在这里晚了几年,但我一直在寻找类似的东西,所以对此进行了深入研究。您使用的主要模式是这样的:
objRegExp.Pattern = "(\'.*(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\!)?" _
& "($?[a-z]{1,3}$?[0-9]{1,7}(\:$?[a-z]{1,3}$?[0-9]{1,7})?" _
& "|$[a-z]{1,3}\:$[a-z]{1,3}" _
& "|[a-z]{1,3}\:[a-z]{1,3}" _
& "|$[0-9]{1,7}\:$[0-9]{1,7}" _
& "|[0-9]{1,7}\:[0-9]{1,7}" _
& "|[a-z_\][a-z0-9_\.]{0,254})"
Basically you have six alternatives for a range reference (lines 3-8), any of which will produce a match by itself, with two alternatives for an optional filename/sheet name prefix (lines 1-2).
基本上,对于范围引用(第 3-8 行),您有六个备选方案,其中任何一个都将自行生成匹配项,还有两个备选方案用于可选的文件名/工作表名称前缀(第 1-2 行)。
For the two prefix alternatives, the only difference is that the first is wrapped in single quotes, with an extra dot star after the initial quote. These single quotes occur mainly when there is a space in a sheet name. The purpose of the dot star, matching unconstrained text after an initial single quote, is unclear and it appears to create problems. I'll discuss those problems below. Besides that the two alternative prefixes are the same, and I'll refer to them collectively as the Optional External Prefix (OEP).
对于这两个前缀替代方案,唯一的区别是第一个用单引号括起来,在初始引号后有一个额外的点星。这些单引号主要出现在工作表名称中有空格时。点星在初始单引号后匹配不受约束的文本的目的尚不清楚,它似乎会产生问题。我将在下面讨论这些问题。除此之外,这两个替代前缀是相同的,我将它们统称为可选外部前缀 (OEP)。
The OEP has its own two optional prefixes (the same in either alternative). The first is for the workbook name, an open-ended dot star in brackets.
OEP 有它自己的两个可选前缀(任何一种都相同)。第一个是工作簿名称,括号中的开放式点星。
(\[.*\])?
The second is for a "3D" cell reference, with two sheet names separated by a colon; it is the initial sheet name including the colon. The pattern here is a negated character class allowing up to 31 characters of anything except forward slash, back slash, question mark, asterisk, brackets, or colon, followed by a colon:
第二个用于“3D”单元格引用,两个工作表名称用冒号分隔;它是包含冒号的初始工作表名称。这里的模式是一个否定字符类,允许最多 31 个字符的任何字符,除了正斜杠、反斜杠、问号、星号、括号或冒号,后跟一个冒号:
([^\:\\/\?\*\[\]]{1,31}\:)?
Finally for the OEP is its only required part: a sheet name, same as the optional sheet name but with no colon. The effect is (if these all worked correctly) that the required sheet name will match if it can, and then only if there is a 3d reference or additional prior bracketed text will its optional prefixes also match.
最后,OEP 是唯一必需的部分:工作表名称,与可选工作表名称相同,但没有冒号。效果是(如果这些都正常工作)所需的工作表名称将匹配(如果可以),然后仅当存在 3d 参考或附加的先前括号文本时,其可选前缀也会匹配。
Issues with the Workbook/Sheet name prefix:First, the dot star at the beginning of the first line is over-inclusive. Similarly, the negated character class for the sheet name appears to need additional characters including parens, comma, plus, minus, equals, and bang. Otherwise, extra material is interpreted as part of the sheet name. On my testing, this overinclusion happened with any of these:
工作簿/工作表名称前缀的问题:首先,第一行开头的点星包含过多。同样,工作表名称的否定字符类似乎需要其他字符,包括括号、逗号、加号、减号、等号和 bang。否则,额外的材料将被解释为图纸名称的一部分。在我的测试中,这种过度包含发生在以下任何一种情况下:
=SUM(Sheet1!A1,Sheet2!A2)
=Sheet1!A1+Sheet2!A2
=Sheet1!A1-Sheet2!A2
Sheet names can include some of these characters, so accounting for that would require some additional measure. For instance, a sheet could be named "(Sheet1)", giving an odd formula like:
工作表名称可以包含其中一些字符,因此考虑到这一点需要一些额外的措施。例如,一张表可以命名为“(Sheet1)”,给出一个奇怪的公式,如:
=SUM('(Sheet1)'!A1:A2)
You'd like to get the inner parens with the sheet name there, but not the outer paren. Excel puts the single quotes on that one, as it would with a space in the sheet name. You could then exclude parens in the non-single quote version since within the single quote it's ok. But then beware Excel seems to even allow single quotes in sheet names. Taking these naming quirks to the extreme, I just successfully named a sheet "Hi'Sheet1'SUM('Sheet2'!A1,A2)!". That's absurd but it points to what could happen. I learned in doing this that if I include a single quote in a sheet name, formulas escape the single quote with a second single quote. So a SUM(A1:A2) referring to the sheet I just created ends up looking like this:
您希望在那里获得带有工作表名称的内部括号,而不是外部括号。Excel 将单引号放在该单引号上,就像工作表名称中带有空格一样。然后,您可以在非单引号版本中排除括号,因为在单引号内就可以了。但是要注意 Excel 似乎甚至允许在工作表名称中使用单引号。将这些命名怪癖发挥到极致,我刚刚成功地命名了一个工作表“Hi'Sheet1'SUM('Sheet2'!A1,A2)!”。这很荒谬,但它指出了可能发生的事情。我在这样做时了解到,如果我在工作表名称中包含单引号,则公式会用第二个单引号转义单引号。所以 SUM(A1:A2) 引用我刚刚创建的工作表最终看起来像这样:
=SUM('Hi''Sheet1''SUM(''Sheet2''!A1,A2)!'!A1:A2)
That actually does give some insight into the Excel parser itself. I suspect to adequately deal with this you may want separately (outside the regex) to compare the potential sheet names or workbook names to the actual sheet names, as you have done with the named ranges.
这实际上确实让我们对 Excel 解析器本身有了一些了解。我怀疑要充分处理这个问题,您可能希望单独(在正则表达式之外)将潜在的工作表名称或工作簿名称与实际工作表名称进行比较,就像您对命名范围所做的那样。
This leads to the six forms of cell references allowed in the regex (any one of which, if met, will produce a match):
这导致了正则表达式中允许的六种形式的单元格引用(如果满足其中任何一种,都将产生匹配):
1.) A one-cell or multi-cell range with rows and columns
1.) 具有行和列的单单元格或多单元格范围
"($?[a-z]{1,3}$?[0-9]{1,7}(\:$?[a-z]{1,3}$?[0-9]{1,7})?"
The open paren here is closed at the end of the 6 options. Otherwise, this line allows a basic cell reference of the type "$A$1", "A1", "$A1", "A$1", or any combination of these in a multi-cell range ("$A1:A$2", etc.).
此处打开的括号在 6 个选项的末尾关闭。否则,此行允许使用“$A$1”、“A1”、“$A1”、“A$1”类型的基本单元格引用,或多单元格范围内这些类型的任意组合(“$A1:A$2 “, 等等。)。
2.) A full-column or multi-column range with absolute references only
2.) 仅包含绝对引用的全列或多列范围
"|$[a-z]{1,3}\:$[a-z]{1,3}"
This one allows a cell reference of the type "$A:$B" with a dollar sign on both. Note a dollar sign on only one side will not match.
这个允许类型为“$A:$B”的单元格引用,两者都带有美元符号。请注意,只有一侧的美元符号不匹配。
3.) A full-column or multi-column range with relative references only
3.) 仅具有相对引用的全列或多列范围
"|[a-z]{1,3}\:[a-z]{1,3}"
This line is like the last, but matches only with no dollar signs. Note a dollar sign on only one side will not match here either.
此行与最后一行类似,但仅匹配不带美元符号的行。请注意,只有一侧的美元符号在这里也不匹配。
4.) A full-row or multi-row range with absolute references only
4.) 仅具有绝对引用的全行或多行范围
"|$[0-9]{1,7}\:$[0-9]{1,7}"
This line allows a cell reference of the type "$1:$2" with a dollar sign on both.
该行允许使用“$1:$2”类型的单元格引用,两者都带有美元符号。
5.) A full-row or multi-row range with relative references only
5.) 仅具有相对引用的全行或多行范围
"|[0-9]{1,7}\:[0-9]{1,7}"
This version is like the last, but matches only with no dollar signs.
此版本与上一个版本类似,但仅匹配不带美元符号。
6.) Other text that could be a named range
6.) 可以是命名范围的其他文本
"|[a-z_\][a-z0-9_\.]{0,254})"
Finally, the sixth option allows text. This text is compared to actual named ranges later in sub.
最后,第六个选项允许文本。此文本将与 sub 后面的实际命名范围进行比较。
The main omission that I see here is ranges that have both absolute and relative references, of the type "A:$A" or "1:$1". While $A:A is captured because it includes "A:A", "A:$A" is not captured. You could address this and simplify the regex by combining 2 and 3 and combining 4 and 5 with optional dollar signs:
我在这里看到的主要遗漏是具有绝对和相对引用的范围,类型为“A:$A”或“1:$1”。虽然 $A:A 被捕获是因为它包含“A:A”,但不会捕获“A:$A”。您可以通过将 2 和 3 以及 4 和 5 与可选的美元符号组合来解决这个问题并简化正则表达式:
objRegExp.Pattern = "(\'.*(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\'\!" _
& "|(\[.*\])?([^\:\\/\?\*\[\]]{1,31}\:)?[^\:\\/\?\*\[\]]{1,31}\!)?" _
& "($?[a-z]{1,3}$?[0-9]{1,7}(\:$?[a-z]{1,3}$?[0-9]{1,7})?" _
& "|$?[a-z]{1,3}\:$?[a-z]{1,3}" _
& "|$?[0-9]{1,7}\:$?[0-9]{1,7}" _
& "|[a-z_\][a-z0-9_\.]{0,254})"
Combining these further would seem to come up against the everything-is-optional problem.
进一步结合这些似乎会遇到一切都是可选的问题。
One other issue is in the initial regex pattern for matching strings, which you use to expunge potential ranges that fall inside a quoted string: objRegExp.Pattern = "\"".*\""" When I test this on a formula with a string at the beginning and end of a formula, the greediness of the dot star captures everything from the initial quote to the final quote (in other words it interprets the entire formula as one big quoted string, even though there is non-string material in the middle). It appears you can fix this by making the dot star lazy (adding a question mark after it). That raises questions about quotes within quotes, but they may not be a problem. For instance, I tested this formula:
另一个问题是匹配字符串的初始正则表达式模式,您可以使用它来清除落在带引号的字符串内的潜在范围:objRegExp.Pattern = "\"".*\"""字符串在公式的开头和结尾,点星的贪婪性捕获了从初始引用到最后引用的所有内容(换句话说,它将整个公式解释为一个大引用字符串,即使其中有非字符串材料中间)。看来您可以通过使点星懒惰(在其后添加问号)来解决此问题。这引发了有关引号内引号的问题,但它们可能不是问题。例如,我测试了这个公式:
="John loves his A1 steak sauce, but said the ""good A1 steak sauce price"" is $" & A2+A3 & " less than the ""bad price"" of $" & A4 & "."
With cell values plugged in, this formula evaluates to:
插入单元格值后,此公式的计算结果为:
John loves his A1 steak sauce, but said the "good A1 steak sauce price" is $5 less than the "bad price" of $8.
约翰喜欢他的 A1 牛排酱,但说“好的 A1 牛排酱价格”比“坏价格”的 8 美元低 5 美元。
With the lazy modifier added to your string pattern, both versions of "A1" above were recognized as occurring within a string and so were expunged, while A2, A3 and A4 were recognized as cell references.
将惰性修饰符添加到您的字符串模式后,上面的“A1”的两个版本都被识别为出现在字符串中,因此被删除,而 A2、A3 和 A4 被识别为单元格引用。
I'm sure there are some technical issues with some of my language above, but hopefully the analysis is still useful.
我确信上面的一些语言存在一些技术问题,但希望分析仍然有用。
回答by Otto H?nninen
Thanks Ben (I'm new to post here, even though Stackoverflow has caught my attention for years for high quality technical stuff, so I'm not sure if I read this page correctly for the author J)
谢谢 Ben(我是在这里发帖的新手,尽管 Stackoverflow 多年来一直因高质量的技术内容而引起我的注意,所以我不确定我是否为作者 J 正确阅读了此页面)
I tried the posted solutions (testing, testing updated, as well as the one using range.precendents (which as correctly pointed, does not cover references to other sheets or other workbooks) and found a minor flaw: the external sheet name is enclosed in 'single quotation marks' only if it is a number; if it contains space (and possibly other characters as Ben (?) listed in the orginal post. with a simple addition to the regEx (opening [) this can be corrected (added "[", see code below). In addition, for my own purpose I converted the sub to a function that will return a comma-separated list with duplicates removed (note, this removes just identical reference notation, not cells that are included in multiple ranges):
我尝试了发布的解决方案(测试,测试更新,以及使用 range.precendents 的解决方案(正确指出,不包括对其他工作表或其他工作簿的引用)并发现一个小缺陷:外部工作表名称包含在'单引号' 仅当它是一个数字时;如果它包含空格(可能还有其他字符如 Ben (?) [",请参阅下面的代码。此外,出于我自己的目的,我将 sub 转换为一个函数,该函数将返回一个删除重复项的逗号分隔列表(注意,这仅删除了相同的引用符号,而不是包含在多个单元格中的单元格范围):
Public Function CellReflist(Optional r As Range) ' single cell
Dim result As Object: Dim testExpression As String: Dim objRegEx As Object
If r Is Nothing Then Set r = ActiveCell ' Cells(1, 2) ' INPUT THE CELL HERE , e.g. RANGE("A1")
Set objRegEx = CreateObject("VBScript.RegExp")
objRegEx.IgnoreCase = True: objRegEx.Global = True: objRegEx.Pattern = """.*?""" ' remove expressions
testExpression = CStr(r.Formula)
testExpression = objRegEx.Replace(testExpression, "")
'objRegEx.Pattern = "(([A-Z])+(\d)+)" 'grab the address
objRegEx.Pattern = "(['\[].*?['!])?([[A-Z0-9_]+[!])?($?[A-Z]+$?(\d)+(:$?[A-Z]+$?(\d)+)?|$?[A-Z]+:$?[A-Z]+|($?[A-Z]+$?(\d)+))"
If objRegEx.Test(testExpression) Then
Set result = objRegEx.Execute(testExpression)
If result.Count > 0 Then CellReflist = result(0).Value
If result.Count > 1 Then
For i = 1 To result.Count - 1 'Each Match In result
dbl = False ' poistetaan tuplaesiintymiset
For j = 0 To i - 1
If result(i).Value = result(j).Value Then dbl = True
Next j
If Not dbl Then CellReflist = CellReflist & "," & result(i).Value 'Match.Value
Next i 'Match
End If
End If
End Function
结束函数