vb.net 通过进程 ID 获取进程的 CPU 使用率

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时间:2020-09-17 12:16:50  来源:igfitidea点击:

Get CPU Usage for Process by Process ID

.netvb.netcpucpu-usagepid

提问by Brady

I have a process ID, and I need to get the CPU usage a.k.a % Processor Timeof the process.

我有一个进程 ID,我需要获取进程的 CPU 使用率,也就是% Processor Time

For example, here is a simple function to return the CPU usage of AppName:

例如,这里有一个简单的函数来返回 AppName 的 CPU 使用率:

Private Function Get_CPU_Usage(AppName as String)
   Dim AppCPU As New PerformanceCounter("Process", "% Processor Time", AppName, True)
   Return AppCPU.NextValue
End Function

It might be wrong but it's just an example.

这可能是错误的,但这只是一个例子。

I need to do something like this:

我需要做这样的事情:

Private Function Get_CPU_Usage(ProcessID as Integer)
   Dim AppCPU As New PerformanceCounter("Process", "% Processor Time", ProcessID, True)
   Return AppCPU.NextValue
End Function

Note ProcessID vs AppName. I have multiple processes running with the same name; each application's PID is stored in my program. I know I can iterate through...

注意 ProcessID 与 AppName。我有多个运行同名的进程;每个应用程序的 PID 都存储在我的程序中。我知道我可以迭代...

PerformanceCounter("Process", "ID Process", AppName, True)

to find the process name, like app, app#1, app#2, but it seems inefficient and sloppy.

找到进程名称,如app、app#1、app#2,但看起来效率低下且马虎。

What is the recommended procedure here?

这里推荐的程序是什么?

回答by Brady

Thanks to Hans Passantfor the link to the answer in C# form, here is the VB.net function converted from Performance Counter by Process I instead of name:

感谢Hans Passant以 C# 形式提供答案的链接,这是由 Process I 而不是 namePerformance Counter转换的 VB.net 函数:

Public Shared Function GetProcessInstanceName(ByVal PID As Integer) As String
    Dim cat As New PerformanceCounterCategory("Process")
    Dim instances() = cat.GetInstanceNames()
    For Each instance In instances
        Using cnt As PerformanceCounter = New PerformanceCounter("Process", "ID Process", instance, True)
            Dim val As Integer = CType(cnt.RawValue, Int32)
            If val = PID Then
                Return instance
            End If
        End Using
    Next
End Function