Python 等效于包含的 unicode 字符串
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unicode string equivalent of contain
提问by aceminer
I have an error when trying to use contain in python.
尝试在 python 中使用包含时出错。
s = u"some utf8 words"
k = u"one utf8 word"
if s.contains(k):
print "contains"
How do i achieve the same result?
我如何达到相同的结果？
Example with normal ASCII string
带有普通 ASCII 字符串的示例
s = "haha i am going home"
k = "haha"
if s.contains(k):
print "contains"
I am using python 2.7.x
我正在使用 python 2.7.x
采纳答案by frnhr
The same for ascii and utf8 strings:
ascii 和 utf8 字符串相同：
if k in s:
print "contains"
There is no contains()on either ascii or uft8 strings:
contains()ascii 或 uft8 字符串都没有：
>>> "strrtinggg".contains
AttributeError: 'str' object has no attribute 'contains'
What you can use instead of containsis findor index:
您可以使用的contains是findor index：
if k.find(s) > -1:
print "contains"
or
或者
try:
k.index(s)
except ValueError:
pass # ValueError: substring not found
else:
print "contains"
But of course, the inoperator is the way to go, it's much more elegant.
但是当然，in运算符是要走的路，它要优雅得多。
回答by Daniel
There is no difference between strand unicode.
str和之间没有区别unicode。
print u"ábc" in u"some ábc"
print "abc" in "some abc"
is basically the same.
基本上是一样的。
回答by Ajay
Strings don't have "contain" attribute.
字符串没有“包含”属性。
s = "haha i am going home"
s_new = s.split(' ')
k = "haha"
if k in s_new:
print "contains"
I guess you want to achieve this
我猜你想实现这一目标
回答by Harvey
Testing of string existance in string
字符串中字符串存在的测试
string = "Little bear likes beer"
if "beer" in string:
print("Little bear likes beer")
else:
print("Little bear is driving")
