如何在java中将字符串转换为xml文件

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/3888033/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-14 06:23:14  来源:igfitidea点击:

How to convert string to xml file in java

javaxml

提问by mohan

 <?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><LoginResponse xmlns="http://tempuri.org/QuestIPhoneWebService/QuestIPhoneWebService"><LoginResult>&lt;RETURN_VALUE&gt;&lt;ERROR RESULT= '-1' DESC = 'The password entered into the system is not valid. Please check your password and try again.'/&gt;&lt;/RETURN_VALUE&gt;</LoginResult></LoginResponse></soap:Body></soap:Envelope>

Hi I am getting the value from webservices. I want to convert above string to xml can anybody tell how to convert string to xml file in java

嗨,我正在从网络服务中获得价值。我想将上面的字符串转换为 xml 谁能告诉如何在 java 中将字符串转换为 xml 文件

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<LoginResponse xmlns="http://tempuri.org/QuestIPhoneWebService/QuestIPhoneWebService">
<LoginResult>
&lt;ROOT xmlns:sql="urn:schemas-microsoft-com:xml-sql"&gt;&lt;LOGIN_DETAILS USER_ID="testpub2" COMPANY_ID="1" USER_NAME=" aaa" SYSTEM_USER_ID="6976" USER_EMAIL_ID="[email protected]" TOKEN_STRING="A93805F1F1C340F5A8155FDD9B77E595" DISCLAIMER_AGREED="1" USER_ENABLED="1" USER_COMPANY_ENABLED="1" USER_TYPE="2" LOGIN_EXPIRY_DAYS="999" TOKEN_CREATION_DATE="2010-10-01T16:04:26" MOBILE_ENABLED="1" USER_COMPANY_MOBILE_ENABLED="1"/&gt;&lt;COMPANY_DETAILS CLIENT_TYPE_ID="8"/&gt;&lt;USER_SETTINGS&gt;&lt;QUEST_GROUP ID="14293" NAME="World" ASSIGN_NUM="14"/&gt;&lt;INDEX_PROVIDER ID="14251" NAME="QUEST (Default)"/&gt;&lt;STOCK_IDENTIFIER ID="57" NAME="TICKER"/&gt;&lt;/USER_SETTINGS&gt;&lt;PERMISSIONS&gt;&lt;QUEST_FUNCTIONS&gt;&lt;FUNCTION NAME="charting" ID="501" ACCESS="1"/&gt;&lt;FUNCTION NAME="modeller" ID="512" ACCESS="1"/&gt;&lt;FUNCTION NAME="momentum" ID="513" ACCESS="1"/&gt;&lt;FUNCTION NAME="portfolio" ID="516" ACCESS="1"/&gt;&lt;FUNCTION NAME="search" ID="518" ACCESS="1"/&gt;&lt;FUNCTION NAME="sensitivity" ID="521" ACCESS="1"/&gt;&lt;FUNCTION NAME="statistics" ID="524" ACCESS="1"/&gt;&lt;FUNCTION NAME="strategy" ID="525" ACCESS="1"/&gt;&lt;FUNCTION NAME="summary" ID="526" ACCESS="1"/&gt;&lt;FUNCTION NAME="triangle" ID="528" ACCESS="1"/&gt;&lt;FUNCTION NAME="valuation" ID="529" ACCESS="1"/&gt;&lt;FUNCTION NAME="commentary" ID="530" ACCESS="1"/&gt;&lt;FUNCTION NAME="CITN" ID="534" ACCESS="1"/&gt;&lt;FUNCTION NAME="batch report" ID="553" ACCESS="1"/&gt;&lt;FUNCTION NAME="ModellerWS" ID="557" ACCESS="1"/&gt;&lt;FUNCTION NAME="Sector Analysis" ID="562" ACCESS="1"/&gt;&lt;/QUEST_FUNCTIONS&gt;&lt;ADMIN_FUNCTIONS&gt;&lt;FUNCTION NAME="administrator" ID="531" ACCESS="0"/&gt;&lt;FUNCTION NAME="author" ID="532" ACCESS="1"/&gt;&lt;FUNCTION NAME="publisher" ID="533" ACCESS="0"/&gt;&lt;FUNCTION NAME="editor" ID="539" ACCESS="0"/&gt;&lt;/ADMIN_FUNCTIONS&gt;&lt;/PERMISSIONS&gt;&lt;/ROOT&gt;
10-04 14:30:08.696: DEBUG/login result is(439): </LoginResult></LoginResponse></soap:Body></soap:Envelope>

the child node are coming like this USER_ID="testpub2" I have to convert xnode and get the value how to covert xml node? and take the value using saxparser. is can I take the value directly?

子节点就像这样 USER_ID="testpub2" 我必须转换 xnode 并获取值如何转换 xml 节点?并使用 saxparser 取值。我可以直接取值吗?

采纳答案by Suresh Kumar

The below code converts a String to an XML document. Once you have the document, you can navigate the nodes or you can write to a file etc.

下面的代码将字符串转换为 XML 文档。获得文档后,您可以导航节点或写入文件等。

import java.io.*;
import javax.xml.parsers.*;
import org.w3c.dom.*;
import org.xml.sax.*;

public class Util {

    public static Document stringToDom(String xmlSource) 
            throws SAXException, ParserConfigurationException, IOException {
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();
        return builder.parse(new InputSource(new StringReader(xmlSource)));
    }
}

回答by amra

public void writeFile(String yourXML){
    BufferedWriter out = new BufferedWriter(new FileWriter("outfilename.xml"));
    try { 
        out.write(yourXML);
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        out.close();
    }
}