C++ 如何将字符数组转换为字符串？
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原文地址: http://stackoverflow.com/questions/8960087/
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How to convert a char array to a string?
提问by kingsmasher1
Converting a C++ stringto a char array is pretty straightorward using the c_strfunction of string and then doing strcpy. However, how to do the opposite?
string使用c_strstring 函数将 C++转换为 char 数组非常简单，然后执行strcpy. 然而，如何做相反的事情呢？
I have a char array like: char arr[ ] = "This is a test";to be converted back to:
string str = "This is a test.
我有一个字符数组，如：char arr[ ] = "This is a test";要转换回：
string str = "This is a test。
回答by Mysticial
The stringclass has a constructor that takes a NULL-terminated C-string:
本string类有一个构造函数一个NULL结尾的C字符串：
char arr[ ] = "This is a test";
string str(arr);
// You can also assign directly to a string.
str = "This is another string";
// or
str = arr;
回答by stackPusher
Another solution might look like this,
另一种解决方案可能如下所示，
char arr[] = "mom";
std::cout << "hi " << std::string(arr);
which avoids using an extra variable.
这避免了使用额外的变量。
回答by Yola
There is a small problem missed in top-voted answers. Namely, character array may contain 0. If we will use constructor with single parameter as pointed above we will lose some data. The possible solution is:
最高投票的答案中遗漏了一个小问题。也就是说，字符数组可能包含 0。如果我们使用上面指出的带有单个参数的构造函数，我们将丢失一些数据。可能的解决方案是：
cout << string("123#include <stdio.h>
#include <iostream>
#include <stdlib.h>
#include <string>
using namespace std;
int main ()
{
char *tmp = (char *)malloc(128);
int n=sprintf(tmp, "Hello from Chile.");
string tmp_str = tmp;
cout << *tmp << " : is a char array beginning with " <<n <<" chars long\n" << endl;
cout << tmp_str << " : is a string with " <<n <<" chars long\n" << endl;
free(tmp);
return 0;
}
123") << endl;
cout << string("123H : is a char array beginning with 17 chars long
Hello from Chile. :is a string with 17 chars long
123", 8) << endl;
Output is:
输出是：
123
123 123
123
123 123
回答by Cristian
OUT:
出去：
##代码##