xcode 关闭通过 Popup 呈现的 ViewController
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Dismiss ViewController that is presented via Popup
提问by sj.cleaver
So i am creating an ipad recipe based app using storyboards. Just to give you an idea of the structure of my program here is the flow of View controllers:
所以我正在使用故事板创建一个基于 ipad 食谱的应用程序。只是为了让您了解我的程序结构，这里是视图控制器的流程：
ViewController --Modally--> PreviewViewController --Modally--> RecipeViewController --Popup--> IngredientsViewController
ViewController --Modally--> PreviewViewController --Modally--> RecipeViewController --Popup-->成分视图控制器
All of this has been done in storyboarding. I created the IngredientsViewControllerand have linked it up to the RecipeViewControllerto be displayed as a popup, which works fine. However i want to be able to dismiss the IngredientsViewControllerprogramatically (because i've implemented voice command features). The problem is i can't seem to access the IngredientsViewControllerto dismiss it. (appologies i can't yet post any pictures).
所有这些都是在故事板中完成的。我创建了IngredientsViewController并将其链接RecipeViewController到要显示为弹出窗口的 ，这很好用。但是我希望能够以IngredientsViewController编程方式关闭（因为我已经实现了语音命令功能）。问题是我似乎无法访问IngredientsViewController以关闭它。（抱歉，我还不能发布任何图片）。
I am using the following code to present the IngredientsViewControllerprogramatically (from within RecipeViewController):
我正在使用以下代码以IngredientsViewController编程方式（从 内RecipeViewController）呈现：
[self performSegueWithIdentifier:@"ingr" sender:nil];
Which works fine to display the popup, but i cant dismiss it. I've tried to access it through the hierarchy of view controllers but cannot seem to find it, i would assume that it would be at the top of the stack, but apparently not? I've tried things like:
显示弹出窗口效果很好，但我不能忽略它。我试图通过视图控制器的层次结构访问它，但似乎找不到它，我认为它会在堆栈的顶部，但显然不是？我试过这样的事情：
[self.presentedViewController dismissViewControllerAnimated:YES completion:nil];
Again this was called from within RecipeViewController. But that simply dismisses the RecipeViewControllerand not the IngredientsViewControllerthat is being presented by popup.
这又是从内部调用的RecipeViewController。但这只是忽略了弹出窗口呈现的RecipeViewController而不是IngredientsViewController。
Just to be clear the IngredientsViewControlleris not a UIPopoverController, it is a normal viewControllercreated in storyboard, and its segue style is popup linked to a button in the RecipeViewController.
需要明确的IngredientsViewController是UIPopoverController，它不是，它是viewController在情节提要中创建的普通样式，并且它的转场样式弹出链接到RecipeViewController.
Any help would be greatly appreciated. Thanks!
任何帮助将不胜感激。谢谢！
采纳答案by Rakesh
UIPopoverController *popOver = (UIPopoverController *)self.presentedViewController;
[popOver dismissPopoverAnimated:YES];
This should do the trick if your destination view controller is a UIPopoverController
如果您的目标视图控制器是一个 UIPopoverController
回答by lolkyfan
Have you tried presentViewController:animated:completion:instead of performSegueWithIdentifier:?
你试过presentViewController:animated:completion:代替performSegueWithIdentifier:吗？
