如果我有以下情况：

{"hdrs": ["Make","Model","Year"],
 "data" : [ 
   {"Make":"Honda","Model":"Accord","Year":"2008"}
   {"Make":"Toyota","Model":"Corolla","Year":"2008"}
   {"Make":"Honda","Model":"Pilot","Year":"2008"}]
}

我有一个" hdrs"名称(即" Make")，如何引用" data"数组实例？
似乎data [" Make"] [0]应该可以正常工作...但是无法获得正确的参考

编辑

很抱歉。我可以遍历hdrs来获取每个hdr名称，但是我需要使用hdrs的每个实例值来查找data中的所有数据元素(不确定哪个更好)。解释)。而且我会将其包含在变量" t"中，因为它是JSON(赞赏重新标记)，我希望能够使用类似以下内容的引用：t.data [hdrs [i]] [j]

解决方案

回答

也许尝试数据[0]。

回答

关闭，我们将使用

var x = data[0].Make;
var z = data[0].Model;
var y = data[0].Year;

回答

那么，像这样吗？

var theMap = /* the stuff you posted */;
var someHdr = "Make";
var whichIndex = 0;
var correspondingData = theMap["data"][whichIndex][someHdr];

如果我对理解正确，那应该可以。

回答

我不得不稍微修改一下代码：

var x = {"hdrs": ["Make","Model","Year"],
         "data" : [ 
           {"Make":"Honda","Model":"Accord","Year":"2008"},
           {"Make":"Toyota","Model":"Corolla","Year":"2008"},
           {"Make":"Honda","Model":"Pilot","Year":"2008"}]
        };

        alert( x.data[0].Make );

编辑：响应编辑

var x = {"hdrs": ["Make","Model","Year"],
         "data" : [ 
           {"Make":"Honda","Model":"Accord","Year":"2008"},
           {"Make":"Toyota","Model":"Corolla","Year":"2008"},
           {"Make":"Honda","Model":"Pilot","Year":"2008"}]
        };
var Header = 0; // Make
for( var i = 0; i <= x.data.length - 1; i++ )
{
    alert( x.data[i][x.hdrs[Header]] );
}

回答

var x = {"hdrs": ["Make","Model","Year"],
 "data" : [ 
   {"Make":"Honda","Model":"Accord","Year":"2008"}
   {"Make":"Toyota","Model":"Corolla","Year":"2008"}
   {"Make":"Honda","Model":"Pilot","Year":"2008"}]
};

x.data[0].Make == "Honda"
x['data'][0]['Make']  == "Honda"

你有你的数组/哈希查找向后:)

回答

我们显示的代码在语法上不正确；它需要一些逗号。我得到这个工作：

$foo = {"hdrs": ["Make","Model","Year"],
 "data" : [ 
   {"Make":"Honda","Model":"Accord","Year":"2008"},
   {"Make":"Toyota","Model":"Corolla","Year":"2008"},
   {"Make":"Honda","Model":"Pilot","Year":"2008"}]
};

然后我可以按以下方式访问数据：

$foo["data"][0]["make"]

回答

首先，我们忘记了数据数组项中的结尾逗号。

尝试以下方法：

var obj_hash = {
    "hdrs": ["Make","Model","Year"],
    "data" : [
        {"Make":"Honda","Model":"Accord","Year":"2008"},
        {"Make":"Toyota","Model":"Corolla","Year":"2008"},
        {"Make":"Honda","Model":"Pilot","Year":"2008"},
    ]
};

var ref_data = obj_hash.data;

alert(ref_data[0].Make);

@Kent Fredric：请注意，并不是必须要使用最后一个逗号，但是可以使我们更轻松地移动行(即，如果在最后一行之后移动或者添加，而没有逗号，则必须特别记得要加一个。我认为最好始终使用逗号结尾。)

回答

我不确定我是否理解问题，但是...

假设上述JSON是var obj，则需要：

obj.data[0]["Make"] // == "Honda"

如果我们只想引用第一个标头引用的字段，则将类似于：

obj.data[0][obj.hdrs[0]] // == "Honda"

回答

在答案的帮助下(并且正确地使内部和外部循环正确执行之后)，我开始工作了：

var t = eval( "(" + request + ")" ) ;
for (var i = 0; i < t.data.length; i++) {
 myTable +=    "<tr>";
 for (var j = 0; j < t.hdrs.length; j++) {
  myTable += "<td>" ;
   if (t.data[i][t.hdrs[j]] == "") {myTable += " " ; }
    else { myTable += t.data[i][t.hdrs[j]] ; }
  myTable += "</td>";
 }
 myTable +=    "</tr>";
}