java javax.xml.bind.UnmarshalException - 带有链接异常:
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javax.xml.bind.UnmarshalException - with linked exception:
提问by Sara
I have got receive an xml inputstream with a URLConnection. However when i try to unmarshall the inputstream. It throw an exception. javax.xml.bind.UnmarshalException - with linked exception: [javax.xml.stream.XMLStreamException: ParseError at [row,col]:[53088,40] Message: The reference to entity "T" must end with the ';' delimiter.]
我收到了一个带有 URLConnection 的 xml 输入流。但是,当我尝试解组输入流时。它抛出异常。javax.xml.bind.UnmarshalException - 带有链接异常:[javax.xml.stream.XMLStreamException: ParseError at [row,col]:[53088,40] 消息:对实体“T”的引用必须以“;”结尾 分隔符。]
CODE:
代码:
try {
URL url = new URL(hostURL);
URLConnection urlConnection = url.openConnection();
urlConnection.setRequestProperty("Accept", "application/xml");
urlConnection.setRequestProperty("Authorization", "Basic " + authDetails);
InputStream inputStream = urlConnection.getInputStream();
XMLInputFactory xif = XMLInputFactory.newInstance();
xif.setProperty("javax.xml.stream.isCoalescing", true);
XMLStreamReader xsr = xif.createXMLStreamReader(inputStream);
// Advance to the "Packages" element.
while(xsr.hasNext()) {
if(xsr.isStartElement() && "packages".equals(xsr.getLocalName())) {
break;
}
xsr.next();
}
JAXBContext jaxbContext = JAXBContext.newInstance(Packages.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
packages = (Packages) jaxbUnmarshaller.unmarshal(xsr);
}catch (JAXBException e) {
e.printStackTrace();
}catch (MalformedURLException e) {
e.printStackTrace();
}catch (IOException e) {
e.printStackTrace();
}catch(Exception e){
e.printStackTrace();
}finally{
}
PS: [row,col]:[53088,40] = newproductsite for T&T evol
PS: [row,col]:[53088,40] = T&T evol 的新产品站点
you can find Stack traces in link http://pastebin.com/LuhbnMQq
您可以在链接http://pastebin.com/LuhbnMQq 中找到堆栈跟踪
Guys am new to this thing and stuck with it, any help would be appreciated
伙计们是这件事的新手并坚持下去,任何帮助将不胜感激
BR Sara
BR莎拉
回答by laune
Your XML file isn't well-formed.
您的 XML 文件格式不正确。
newproductsite for T&T evol
You cannot have a '&' in the XML file, it must be represented as
XML 文件中不能有“&”,它必须表示为
&
How was the XML produced? The error is there...
XML 是如何产生的?错误就在那里...
回答by Ralf Wagner
Your xml input is not well formed. In the text newproductsite for T&T evol
the ampersand is a reserved character. It is used for escaping (e.g. <
represents the <
sign or A
is the letter A
. So, after the &
in the text, the parser expects a value and a ;
to see that the escape sequence is finished.
If you want to use the ampersand in your xml elements, it must be escaped e.g. by &
.
您的 xml 输入格式不正确。在文本中,newproductsite for T&T evol
与号是保留字符。它用于转义(例如<
表示<
符号或是A
字母A
。因此,在&
文本中的之后,解析器需要一个值和 a;
以查看转义序列已完成。如果您想在 xml 元素中使用&符号,它必须被转义,例如&
。
To fix the problem the source needs to produce either well-formed xml or you need to sanitize the data you received before processing it. I would recommend the first.
要解决此问题,源需要生成格式良好的 xml,或者您需要在处理之前清理收到的数据。我会推荐第一个。