在Java中获取资源文件夹中的文件
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Get file in the resources folder in Java
提问by Malintha
I want to read the file in my resource folder in my Java project. I used the following code for that
我想读取 Java 项目中资源文件夹中的文件。我为此使用了以下代码
MyClass.class.getResource("/myFile.xsd").getPath();
And I wanted to check the path of the file. But it gives the following path
我想检查文件的路径。但它给出了以下路径
file:/home/malintha/.m2/repository/org/wso2/carbon/automation/org.wso2.carbon.automation.engine/4.2.0-SNAPSHOT/org.wso2.carbon.automation.engine-4.2.0-SNAPSHOT.jar!/myFile.xsd
I get the file path in the maven repository dependency and it is not getting the file. How can I do this?
我在 maven 存储库依赖项中获取了文件路径，但它没有获取该文件。我怎样才能做到这一点？
回答by SudoRahul
You need to give the path of your resfolder.
您需要提供res文件夹的路径。
MyClass.class.getResource("/res/path/to/the/file/myFile.xsd").getPath();
回答by Matt
Is your resource directory in the classpath?
你的资源目录在类路径中吗？
You are not including resource directory in your path:
您没有在路径中包含资源目录：
MyClass.class.getResource("/${YOUR_RES_DIR_HERE}/myFile.xsd").getPath();
回答by Sebastian
It is not possible to access resources of other maven modules. So you need to provide your resource myFile.xsd in your src/main/resourcesor src/test/resourcesfolder.
无法访问其他 maven 模块的资源。所以你需要在你的src/main/resources或src/test/resources文件夹中提供你的资源 myFile.xsd 。
回答by Joop Eggen
The path is correct, though not on the file system, but inside the jar. That is, because the jar was running. A resource never is guaranteed to be a File.
路径是正确的，虽然不在文件系统上，但在 jar 内。也就是说，因为 jar 正在运行。资源永远不能保证是文件。
However if you do not want to use resources, you can use a zip file system. However Files.copywould suffice to copy the file outside the jar. Modifying the file insidethe jar is a bad idea. Better use the resource as "template" to make an initial copy in the user's home (sub-)directory (System.getProperty("user.home")).
但是，如果您不想使用资源，则可以使用zip 文件系统。但是，Files.copy将文件复制到 jar 之外就足够了。修改文件里面的罐子是一个坏主意。最好将资源用作“模板”，以便在用户的主（子）目录 ( System.getProperty("user.home")) 中制作初始副本。
回答by Lukas Masuch
A reliable way to construct a File instance from the resource folder is it to copy the resource as a stream into a temporary File (temp file will be deleted when the JVM exits):
从资源文件夹构造 File 实例的一种可靠方法是将资源作为流复制到临时文件中（JVM 退出时临时文件将被删除）：
public static File getResourceAsFile(String resourcePath) {
try {
InputStream in = ClassLoader.getSystemClassLoader().getResourceAsStream(resourcePath);
if (in == null) {
return null;
}
File tempFile = File.createTempFile(String.valueOf(in.hashCode()), ".tmp");
tempFile.deleteOnExit();
try (FileOutputStream out = new FileOutputStream(tempFile)) {
//copy stream
byte[] buffer = new byte[1024];
int bytesRead;
while ((bytesRead = in.read(buffer)) != -1) {
out.write(buffer, 0, bytesRead);
}
}
return tempFile;
} catch (IOException e) {
e.printStackTrace();
return null;
}
}
回答by gbii
In maven project, lets assume that, we have the file whose name is "config.cnf" and it's location is below.
在 maven 项目中，让我们假设，我们有一个名为“ config.cnf”的文件，它的位置在下面。
/src
/main
/resources
/conf
config.cnf
In IDE (Eclipse), I access this file by using ClassLoader.getResource(..) method, but if I ran this application by using jar, I always across "File not found" exception. Finally, I wrote a method which accessing the file by looking at where app works.
在 IDE (Eclipse) 中，我使用 ClassLoader.getResource(..) 方法访问此文件，但如果我使用 jar 运行此应用程序，我总是遇到“找不到文件”异常。最后，我编写了一个方法，通过查看应用程序的工作位置来访问文件。
public static File getResourceFile(String relativePath)
{
File file = null;
URL location = <Class>.class.getProtectionDomain().getCodeSource().getLocation();
String codeLoaction = location.toString();
try{
if (codeLocation.endsWith(".jar"){
//Call from jar
Path path = Paths.get(location.toURI()).resolve("../classes/" + relativePath).normalize();
file = path.toFile();
}else{
//Call from IDE
file = new File(<Class>.class.getClassLoader().getResource(relativePath).getPath());
}
}catch(URISyntaxException ex){
ex.printStackTrace();
}
return file;
}
If you call this method by sending "conf/config.conf" param, you access this file from both jar and IDE.
如果您通过发送“ conf/config.conf”参数调用此方法，则您可以从 jar 和 IDE 访问此文件。
