使用 bash 测试文件日期
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/1819187/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Test a file date with bash
提问by JeffPHP
I am trying to test how old ago a file was created (in seconds) with bash in an ifstatement. I need creation date, not modification.
我正在尝试在if语句中测试使用 bash 创建文件的时间（以秒为单位）。我需要创建日期，而不是修改。
Do you have any idea how to do this, without using a command like findwith grep?
您知道如何在不使用findwith 之类的命令的情况下执行此操作grep吗？
采纳答案by JeffPHP
Here is the best answer I found at the time being, but it's only for the modification time :
这是我目前找到的最佳答案，但仅适用于修改时间：
expr `date +%s` - `stat -c %Y /home/user/my_file`
回答by Joel
I'm afraid I cann't answer the question for creation time, but for last modification time you can use the following to get the epoch date, in seconds, since filenamewas last modified:
恐怕我无法回答创建时间的问题，但是对于上次修改时间，您可以使用以下内容获取纪元日期（以秒为单位），因为文件名是上次修改的：
date --utc --reference=filename +%s
So you could then so something like:
所以你可以这样：
modsecs=$(date --utc --reference=filename +%s)
nowsecs=$(date +%s)
delta=$(($nowsecs-$modsecs))
echo "File $filename was modified $delta secs ago"
if [ $delta -lt 120 ]; then
# do something
fi
etc..
等等..
UpdateA more elgant way of doing this (again, modified time only): how do I check in bash whether a file was created more than x time ago?
更新一种更优雅的方式（同样，仅限修改时间）：如何在 bash 中检查文件是否是在 x 次之前创建的？
回答by Paused until further notice.
If your system has stat:
如果您的系统有stat：
modsecs=$(stat --format '%Y' filename)
And you can do the math as in Joel's answer.
您可以按照Joel的回答进行数学计算。
回答by ghostdog74
you can use ls with --full-time
您可以将 ls 与 --full-time 一起使用
file1="file1"
file2="file2"
declare -a array
i=0
ls -go --full-time "$file1" "$file2" | { while read -r a b c d time f
do
time=${time%.*}
IFS=":"
set -- $time
hr=;min=;sec=
hr=$(( hr * 3600 ))
min=$(( min * 60 ))
totalsecs=$(( hr+min+sec ))
array[$i]=$totalsecs
i=$((i+1))
unset IFS
done
echo $(( ${array[0]}-${array[1]} ))
}
