Java：String.matches()
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/10261137/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Java : String.matches()
提问by Predoryx
I want to determine whether a string consists of only two words, with one space character between them. The first word should only include alphanumeric characters. The second should include only numbers. An example is: asd 15
我想确定一个字符串是否只包含两个单词，它们之间有一个空格字符。第一个单词应仅包含字母数字字符。第二个应该只包含数字。一个例子是：asd 15
I would like to use String.matches. How can I do this or which regex should I use?
我想用String.matches. 我该怎么做或者我应该使用哪个正则表达式？
Thanks in advance.
提前致谢。
回答by MByD
You look for something like:
你寻找类似的东西：
String regex = "^[A-Za-z]+ [0-9]+$";
Explanation:
解释：
^ the beginning of the string (nothing before the next token)
[A-Za-z]+ at least one, but maybe more alphabetic chars (case insensitive)
a single space (hard to see :) )
[0-9]+ at least one, but maybe more digits
$ end of the string (nothing after the digits)
回答by Juan Alberto López Cavallotti
You can give this regex a try
你可以试试这个正则表达式
"[A-Za-z0-9]+\s[0-9]+"
回答by Kannan
Try this out: String pattern = new String("^[0-9]*[A-Za-z]+ [0-9]+$")
试试这个： String pattern = new String("^[0-9]*[A-Za-z]+ [0-9]+$")
