java Java标签语句和goto
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Java label statement and goto
提问by Ismail Marmoush
Possible Duplicate:
goto keyword in java
可能的重复：
java 中的 goto 关键字
- There is no goto in java, right ?
- Why goto is still considered a keyword then ?
- Label syntax (only properly* used before a loop/if statement ?? ) and called through (label, break label, continue label)
- java中没有goto，对吧？
- 为什么 goto 仍然被认为是一个关键字呢？
- 标签语法（仅在循环/if 语句 ?? 之前正确*使用）并通过（标签、中断标签、继续标签）调用
*properly cause when i used before x=3it couldn't be read after it are there any other cases ?
*正确原因当我之前使用x=3它之后无法读取它还有其他情况吗？
int x = 2;
label: x = 3;
for (int j = 0; j < 5; j++) {
System.out.println(j);
}
label; // Compile error (no local variable label)
回答by Jon Skeet
From section 3.9 of the JLS:
The keywords
constandgotoare reserved, even though they are not currently used. This may allow a Java compiler to produce better error messages if these C++ keywords incorrectly appear in programs.
关键字
constandgoto是保留的，即使它们当前未使用。如果这些 C++ 关键字错误地出现在程序中，这可能允许 Java 编译器生成更好的错误消息。
回答by Jigar Joshi
回答by Pablo Grisafi
1 - There is no goto in Java (the language), there is goto in Java (the virtual machine)
2 - The keywords const and goto are reserved, even though they are not currently used. This may allow a Java compiler to produce better error messages if these C++ keywords incorrectly appear in programs. (from The java language specification)
3 - what is the question?
1 - Java（语言）中没有 goto，Java（虚拟机）中有 goto
2 - 关键字 const 和 goto 是保留的，即使它们当前未使用。如果这些 C++ 关键字错误地出现在程序中，这可能允许 Java 编译器生成更好的错误消息。（来自Java 语言规范）
3 - 问题是什么？
Anyway, read the The java language specification several times before going to SCJP (isn't OCJP now? )
反正去SCJP之前多读几遍Java语言规范（现在不是OCJP了吗？）
