wpf 如何点击页面的一个按钮来改变Windows的框架来源？
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How to click a button of the page to change the source of the frame of Windows?
提问by zhchma
I have a WPF project, I add a frame in the Windows,the source of the frame is the page. I want to achieve clicking a button in the page to change the page of the frame.
我有一个WPF项目，我在Windows中添加了一个框架，框架的来源是页面。我想实现点击页面中的一个按钮来改变框架的页面。
<Window x:Class="MagicArm.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:MagicArm"
Title="MainWindow">
<Frame Name="FrameContent"Source="PageStart.xaml"></Frame>
</Window>
PageStart:
页面开始：
<Page x:Class="MagicArm.PageStart"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
Height="452" Width="800"
Title="PageStart">
<Canvas>
<button name=""> </button>
</Canvas>
回答by Dragos Stoica
EDIT: A functional solution can look like:
编辑：功能性解决方案可能如下所示：
MainWindow XAML:
主窗口 XAML：
<StackPanel>
<Frame Name="frmMainContent" Height="260"
DataContext="MyPageInformation"
Source="{Binding}"
NavigationUIVisibility="Hidden">
</Frame>
</StackPanel>
MainWindow cs:
主窗口 cs:
frmMainContent.Source = new Uri("test1.xaml", UriKind.Relative); // initialize frame with the "test1" view
test1 XAML:
测试 1 XAML：
<Grid>
<Button Click="ButtonBase_OnClick" Background="Red" Height="30" Width="100">Go to page 2</Button>
</Grid>
test1 cs:
测试1 cs：
private void ButtonBase_OnClick(object sender, RoutedEventArgs e)
{
NavigationService ns = NavigationService.GetNavigationService(this);
ns.Navigate(new Uri("test2.xaml", UriKind.Relative));
}
test2 XAML:
测试2 XAML：
<Grid>
<Button Click="ButtonBase_OnClick" Width="100" Height="30" Background="RoyalBlue"> Go to page 1</Button>
</Grid>
test2 cs:
测试2 cs：
NavigationService ns = NavigationService.GetNavigationService(this);
ns.Navigate(new Uri("test1.xaml", UriKind.Relative));
This is a working solution using NavigationService.
这是使用 NavigationService 的有效解决方案。
