bash 如何删除数组中的元素，然后在 Shell 脚本中移动数组？
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How can i delete an element in an array and then shift the array in Shell Script?
提问by tc90
First let me state my problem clearly:
首先让我清楚地说明我的问题：
Ex: Let's pretend this is my array, (the elements don't matter as in my actual code they vary):
例如：让我们假设这是我的数组，（元素并不重要，因为在我的实际代码中它们会有所不同）：
array=(jim 0 26 chris billy 78 hello foo bar)
Now say I want to remove the following elements:
现在说我想删除以下元素：
chris 78 hello
So I did: unset array[$i]while looping through the array.
This removes the elements correctly, however, i end up with an array that looks like this:
所以我做了：unset array[$i]同时循环遍历数组。这将正确删除元素，但是，我最终得到一个如下所示的数组：
array=(jim 0 26 '' billy '' '' foo bar)
I need it to look like this:
我需要它看起来像这样：
array=(jim 0 26 billy foo bar)
where jimis at index 0, 0@1, 26@2, etc..
其中jim位于索引0、0@1、26@2等处。
How do I delete the elements in the array and move the other elements so that there are no null/empty spaces in the array?
如何删除数组中的元素并移动其他元素，以便数组中没有空/空白空间？
Thanks!
谢谢！
回答by chepner
Try this:
尝试这个：
$ array=( "one two" "three four" "five six" )
$ unset array[1]
$ array=( "${array[@]}" )
$ echo ${array[0]}
one two
$ echo ${array[1]}
five six
Shell arrays aren't really intended as data structures that you can add and remove items from (they are mainly intended to provide a second level of quoting for situations like
Shell 数组并不是真正用作可以从中添加和删除项目的数据结构（它们主要用于为以下情况提供第二级引用：
arr=( "one two" "three four" )
somecommand "${arr[@]}"
to provide somecommandwith two, not four, arguments). But this should work in most situations.
提供somecommand两个而不是四个参数）。但这应该适用于大多数情况。
回答by Alexey Pismenny
See http://www.thegeekstuff.com/2010/06/bash-array-tutorial
见http://www.thegeekstuff.com/2010/06/bash-array-tutorial
- Remove an Element from an Array
- 从数组中删除元素
...
...
Unix=('Debian' 'Red hat' 'Ubuntu' 'Suse' 'Fedora' 'UTS' 'OpenLinux');
pos=3
Unix=(${Unix[@]:0:$pos} ${Unix[@]:$(($pos + 1))})
This contracts the array around pos, which the original poster wanted.
这会收缩 pos 周围的数组，这是原始发布者想要的。
回答by mark_infinite
Try this:
尝试这个：
user@pc:~$ array=(jim 0 26 chris billy 78 hello foo bar)
user@pc:~$ for itm2rm in chris 78 hello; do array=(\`echo ${array[@]} | sed "s/\<${itm2rm}\>//g"\`); done ; echo ${array[@]}
jim 0 26 billy foo bar
回答by Clark Kent
this post had been revised and moved to its own post as a more in-depth tutorial how to remove an array element correctly in a for loop
这篇文章已经过修改并移到自己的帖子中作为更深入的教程如何在 for 循环中正确删除数组元素
