python - 从浮点数中删除所有小数
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python - remove all decimals from a float
提问by user3196332
How can I remove all decimal places form a float?
如何从浮点数中删除所有小数位？
a = 100.0
a = 100.0
I want that to become 100
我希望它变成 100
I tried str(a).rstrip('.0'), but it just returned 1
我试过了str(a).rstrip('.0')，但它刚回来1
采纳答案by Paulo Bu
What about converting it to int?
把它转换成int什么？
>>>int(a)
100
Just for the sake of completeness, there are many many ways to remove the decimal part from a string representation of a decimal number, one that I can come up right now is:
为了完整起见，有很多方法可以从十进制数的字符串表示中删除小数部分，我现在可以想到的方法是：
s='100.0'
s=s[:s.index('.')]
s
>>>'100'
Perhaps there's another one more simple.
也许还有一个更简单的。
Hope this helps!
希望这可以帮助！
回答by ederollora
If you do not want to convert it to an int you can also split it.
如果您不想将其转换为 int，您也可以拆分它。
>>> a = 100.25
>>> str(a).split('.')[0]
>>> '100' # result is now a string
回答by Colton Allen
If you're deriving the float you can floor it with //
如果您正在推导浮点数，您可以使用 //
a = 200 / 2 # outputs 100.0
a = 200 // 2 # outputs 100
Faster than typecasting afterwards!
比之后的类型转换更快！
回答by Prateek Gupta
In simple words,int()method in python is the type conversion function similar to float()and str(), and can be used for converting float numbers to int numbers.
简单来说，int()python中的method就是类似于float()and的类型转换函数str()，可以用来将float数转换为int数。
