C++ 如何从子类访问父类的数据成员，当父类和子类的 dat 成员具有相同的名称时
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原文地址: http://stackoverflow.com/questions/11525418/
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How to access parent class's data member from child class, when both parent and child have the same name for the dat member
提问by codeLover
my scenario is as follows::
我的情况如下：
class Parent
{
public:
int x;
}
class Child:public Parent
{
int x; // Same name as Parent's "x".
void Func()
{
this.x = Parent::x; // HOW should I access Parents "x".
}
}
Here how to access Parent's "X" from a member function of Child.
这里如何从 Child 的成员函数访问 Parent 的“X”。
回答by Luchian Grigore
Almost got it:
差点就明白了：
this->x = Parent::x;
thisis a pointer.
this是一个指针。
回答by Chad
Accessing it via the scope resolution operator will work:
通过范围解析运算符访问它会起作用：
x = Parent::x;
However, I would question in what circumstances you want to do this. Your example uses public inheritance which models an "is-a" relationship. So, if you have objects that meet this criteria, but have the same members with different values and/or different meanings then this "is-a" relationship is misleading. There may be some fringe circumstances where this is appropriate, but I would state that they are definitely the exceptions to the rule. Whenever you find yourself doing this, think long and hard about why.
但是，我会质疑您要在什么情况下执行此操作。您的示例使用公共继承来建模“is-a”关系。因此，如果您有满足此条件的对象，但具有具有不同值和/或不同含义的相同成员，那么这种“is-a”关系具有误导性。可能有一些边缘情况是合适的，但我要声明它们绝对是规则的例外。每当您发现自己这样做时，请仔细思考原因。
回答by M. Grzywaczewski
It's only a brief explaination of solutions provided by Luchian Grigore and Mr. Anubis, so if you are curious 'how this works', you should read it further.
这只是 Luchian Grigore 和 Anubis 先生提供的解决方案的简要说明，因此如果您对“这是如何工作的”感到好奇，您应该进一步阅读。
C++ provides a so-called, "scope operator" (::), which is perfectly suited to your task.
C++ 提供了一个所谓的“作用域运算符”( ::)，它非常适合您的任务。
More details are provided at this page. You can combine this operator with class name (Parent) to access parent's xvariable.
此页面提供了更多详细信息。您可以将此运算符与类名 ( Parent)结合使用以访问父级x变量。
