在 JavaScript/CoffeeScript 中确定一个数组是否包含另一个数组的内容
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Determining whether one array contains the contents of another array in JavaScript/CoffeeScript
提问by Zeck
In JavaScript, how do I test that one array has the elements of another array?
在 JavaScript 中，如何测试一个数组是否具有另一个数组的元素？
arr1 = [1, 2, 3, 4, 5]
[8, 1, 10, 2, 3, 4, 5, 9].function_name(arr1) # => true
回答by Explosion Pills
No set function does this, but you can simply do an ad-hoc array intersection and check the length.
没有 set 函数会这样做，但您可以简单地进行临时数组交集并检查长度。
[8, 1, 10, 2, 3, 4, 5, 9].filter(function (elem) {
return arr1.indexOf(elem) > -1;
}).length == arr1.length
A more efficient way to do this would be to use .everywhich will short circuit in falsy cases.
一种更有效的方法是使用.everywhich 将在虚假情况下短路。
arr1.every(elem => arr2.indexOf(elem) > -1);
回答by valentinas
You can use array.indexOf():
您可以使用array.indexOf()：
pseudocode:
伪代码：
function arrayContainsAnotherArray(needle, haystack){
for(var i = 0; i < needle.length; i++){
if(haystack.indexOf(needle[i]) === -1)
return false;
}
return true;
}
回答by tamilmani
function arr(arr1,arr2)
{
for(var i=0;i<arr1.length;i++)
{
if($.inArray(arr1[i],arr2) ==-1)
//here it returns that arr1 value does not contain the arr2
else
// here it returns that arr1 value contains in arr2
}
}
