bash 解压 ZIP 文件并提取未知文件夹名称的内容
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Unzip ZIP file and extract unknown folder name's content
提问by siliconpi
My users will be zipping up files which will look like this:
我的用户将压缩如下所示的文件：
TEMPLATE1.ZIP
|--------- UnknownName
|------- index.html
|------- images
|------- image1.jpg
I want to extract this zip file as follows:
我想按如下方式解压缩这个 zip 文件：
/mysite/user_uploaded_templates/myrandomname/index.html
/mysite/user_uploaded_templates/myrandomname/images/image1.jpg
My trouble is with UnknownName - I do not know what it is beforehand and extracting everything to the "base" level breaks all the relative paths in index.html
我的问题是 UnknownName - 我事先不知道它是什么，将所有内容提取到“基本”级别会破坏 index.html 中的所有相对路径
How can I extract from this ZIP file the contentsof UnknownName?
如何从此 ZIP 文件中提取UnknownName的内容？
Is there anythingbetter than:
有什么比：
1. Extract everything
2. Detect which "new subdidrectory" got created
3. mv newsubdir/* .
4. rmdir newsubdir/
If there is more than one subdirectory at UnknownName level, I can reject that user's zip file.
如果在 UnknownName 级别有多个子目录，我可以拒绝该用户的 zip 文件。
回答by Paused until further notice.
I think your approach is a good one. Step 2 could be improved my extracting to a newly created directory (later deleted) so that "detection" is trivial.
我认为你的方法是一个很好的方法。第 2 步可以改进我提取到新创建的目录（后来删除），以便“检测”是微不足道的。
# Bash (minimally tested)
tempdest=$(mktemp -d)
unzip -d "$tempdest" TEMPLATE1.ZIP
dir=("$tempdest"/*)
if (( ${#dir[@]} == 1 )) && [[ -d $dir ]]
# in Bash, etc., scalar $var is the same as ${var[0]}
mv "$dir"/* /mysite/user_uploaded_templates/myrandomname
else
echo "rejected"
fi
rm -rf "$tempdest"
回答by SiegeX
The other option I can see other than the one you suggested is to use the unzip -jflag which will dump all paths and put all files into the current directory. If you know for certain that each of your TEMPLATE1.ZIPfiles includes an index.htmland *.jpgfiles then you can just do something like:
除了您建议的选项之外，我可以看到的另一个选项是使用该unzip -j标志，该标志将转储所有路径并将所有文件放入当前目录。如果您确定您的每个TEMPLATE1.ZIP文件都包含一个index.html和*.jpg文件，那么您可以执行以下操作：
destdir=/mysite/user_uploaded_templates/myrandomname
unzip -j -d "$destdir"
mkdir "${destdir}/images"
mv "${destdir}/*.jpg" "${destdir}/images"
It's not exactly the cleanest solution but at least you don't have to do any parsing like you do in your example. I can't seem to find any option similar to patch -p#that lets you specify the path level.
这并不是最干净的解决方案，但至少您不必像在示例中那样进行任何解析。我似乎找不到任何类似于patch -p#让您指定路径级别的选项。
回答by David W.
Each zipand unzipcommand differs, but there's usually a way to list the file contents. From there, you can parse the output to determine the unknown directory name.
每个zip和unzip命令都不同，但通常有一种方法可以列出文件内容。从那里，您可以解析输出以确定未知的目录名称。
On Windows, the 1996 Wales/Gaily/van der Linden/Rommel version it is unzip -l.
在 Windows 上，1996 Wales/Gaily/van der Linden/Rommel 版本是unzip -l.
Of course, you could just simply allow the unzip to unzip the files to whatever directory it wants, then use mvto rename the directory to what you want it as.
当然，您可以简单地允许解压缩将文件解压缩到它想要的任何目录，然后使用mv将目录重命名为您想要的。
$tempDir = temp.$$
mv $zipFile temp.$$
cd $tempDir
unzip $zipFile
$unknownDir = * #Should be the only directory here
mv $unknownDir $whereItShouldBe
cd ..
rm -rf $tempDir
It's always a good idea to create a temporary directory for these types of operations in case you end up running two instances of this command.
为这些类型的操作创建一个临时目录总是一个好主意，以防您最终运行此命令的两个实例。
