C# 使用 GetFiles 返回完整路径

C# return full path with GetFiles

提问by user1775334

Use this code for search files in directory:

使用此代码搜索目录中的文件：

FileInfo[] files = null;
string path = some_path;
DirectoryInfo folder = new DirectoryInfo(path);
files = folder.GetFiles("*.*", SearchOption.AllDirectories);

This return only filename and extension (text.exe). How to return full path to file(C:\bla\bla\bla\text.exe)?

这仅返回文件名和扩展名 (text.exe)。如何返回文件的完整路径（C:\bla\bla\bla\text.exe）？

If I use Directory.GetFiles("*.*"), this return full path. But if folder contains point in name(C:\bla\bla\test.0.1), result contains path to folder without file:

如果我使用Directory.GetFiles("*.*")，则返回完整路径。但是如果文件夹包含名称中的点（C:\bla\bla\test.0.1），结果包含没有文件的文件夹的路径：

• 0 C:\bla\bla\bla\text.exe
• 1 C:\bla\bla\test.0.1
• 2 C:\bla\text.exe

• 0 C:\bla\bla\bla\text.exe
• 1 C:\bla\bla\test.0.1
• 2 C:\bla\text.exe

etc.

等等。

采纳答案by Ilya Ivanov

FileInfocontains a FullNameproperty, which you can use to retrieve full path to a file

FileInfo包含一个FullName属性，您可以使用它来检索文件的完整路径

var fullNames = files.Select(file => file.FullName).ToArray();

Check

查看

This code on my machine:

我机器上的这段代码：

FileInfo[] files = null;
string path = @"C:\temp";
DirectoryInfo folder = new DirectoryInfo(path);
files = folder.GetFiles("*.*", SearchOption.AllDirectories);

//you need string from FileInfo to denote full path
IEnumerable<string> fullNames = files.Select(file => file.FullName);

Console.WriteLine ( string.Join(Environment.NewLine, fullNames ) );

prints

印刷

C:\temp.dot 
C:\temp.jpg 
C:\temp.png 
C:\temp.txt 
C:\temp.png 
C:\temp\a.xml 
...

Full solution

完整解决方案

The solution to your problem might look like this:

您的问题的解决方案可能如下所示：

string path = @"C:\temp";
DirectoryInfo folder = new DirectoryInfo(path);
var directories = folder.GetDirectories("*.*", SearchOption.AllDirectories);


IEnumerable<string> directoriesWithDot = 
 directories.Where(dir => dir.Name.Contains("."))
            .Select(dir => dir.FullName);


IEnumerable<string> filesInDirectoriesWithoutDot = 
 directories.Where(dir => !dir.Name.Contains("."))
            .SelectMany(dir => dir.GetFiles("*.*", SearchOption.TopDirectoryOnly))
            .Select(file => file.FullName);


Console.WriteLine ( string.Join(Environment.NewLine, directoriesWithDot.Union(filesInDirectoriesWithoutDot) ) );

回答by Henk Holterman

Each FileInfoobject has a FullNameproperty.

每个FileInfo对象都有一个FullName属性。

---

---

But if folder contains point in name (C:\bla\bla\test.0.1), result contains path to folder without file

但是如果文件夹包含名称中的点（C:\bla\bla\test.0.1），结果包含没有文件的文件夹的路径

This is an entirely different issue with possibly diffeent answers/workarounds. Can you be more specific?
I cannot reproduce this.

这是一个完全不同的问题，可能有不同的答案/解决方法。你可以说得更详细点吗？
我无法重现这一点。

回答by LukeHennerley

You need to use FileInfo.

您需要使用FileInfo.

Directory.GetFiles("", SearchOption.AllDirectories).Select(file => new FileInfo(file).FullName);

回答by David

public static IEnumerable<string> GetAllFilesRecursively(string inputFolder)
    {
        var queue = new Queue<string>();
        queue.Enqueue(inputFolder);
        while (queue.Count > 0)
        {
            inputFolder = queue.Dequeue();
            try
            {
                foreach (string subDir in Directory.GetDirectories(inputFolder))
                {
                    queue.Enqueue(subDir);
                }
            }
            catch (Exception ex)
            {
                Console.Error.WriteLine("GetAllFilesRecursively: " + ex);
            }
            string[] files = null;
            try
            {
                files = Directory.GetFiles(inputFolder);
            }
            catch (Exception ex)
            {
                Console.Error.WriteLine("GetAllFilesRecursively: " + ex);
            }
            if (files != null)
            {
                for (int i = 0; i < files.Length; i++)
                {
                    yield return files[i];
                }
            }
        }
    }

回答by Arshad

you can try this :

你可以试试这个：

void GetFiles()
    {
        DirectoryInfo d= new DirectoryInfo(strFolderPath);
       //file extension for pdf
        var files = d.GetFiles("*.pdf*");
        FileInfo[] subfileInfo = files.ToArray<FileInfo>();

        if (subfileInfo.Length > 0)
        {
            for (int j = 0; j < subfileInfo.Length; j++)
            {
                bool isHidden = ((File.GetAttributes(subfileInfo[j].FullName) & FileAttributes.Hidden) == FileAttributes.Hidden);
                if (!isHidden)
                {
                    string strExtention = th.GetExtension(subfileInfo[j].FullName);
                    if (strExtention.Contains("pdf"))
                    {                            
                        string path = subfileInfo[j].FullName;
                        string name = bfileInfo[j].Name;                           
                    }
                }
            }
        }

回答by Soner G?nül

You can use FileSystemInfo.FullNameproperty.

您可以使用FileSystemInfo.FullName财产。

Gets the full path of the directory or file.

获取目录或文件的完整路径。