来自 Pandas Dataframe 的 Seaborn Violin Plot，每列都有自己独立的小提琴图
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Seaborn Violin Plot from Pandas Dataframe, each column its own separate violin plot
提问by aw94
I have Pandas Dataframe with structure:
我有 Pandas Dataframe 的结构：
A B
0 1 1
1 2 1
2 3 4
3 3 7
4 6 8
How do I generate a Seaborn Violin plot with each column as its own separate violin plot for side-by-side comparison?
如何生成一个 Seaborn Violin 图，每列作为它自己单独的小提琴图进行并排比较？
回答by jezrael
You can first reshape by meltfor groups from columns and then seaborn.violinplot:
您可以首先通过meltfor 来自列的组重新整形，然后seaborn.violinplot：
#old version of pandas
#df = pd.melt(df, var_name='groups', value_name='vals')
df = df.melt(var_name='groups', value_name='vals')
print (df)
groups vals
0 A 1
1 A 2
2 A 3
3 A 3
4 A 6
5 B 1
6 B 1
7 B 4
8 B 7
9 B 8
ax = sns.violinplot(x="groups", y="vals", data=df)
回答by Nathan
seaborn(at least, version 0.8.1; not sure if this is new) supports what you want without messing around with your dataframe at all:
seaborn（至少是 0.8.1 版；不确定这是否是新的）支持您想要的内容，而根本不会弄乱您的数据框：
import pandas as pd
import seaborn as sns
df = pd.DataFrame({'A': [1, 2, 3, 3, 6], 'B': [1, 1, 4, 7, 8]})
sns.violinplot(data=df)
(Note that you do need to set data=df; if you just pass in dfas the first argument (equivalent to setting x=dfin the function call), it seems like it concatenates the columns together and then makes a violin plot of all of the data)
（请注意，您确实需要设置data=df; 如果您只是df作为第一个参数传入（相当于x=df在函数调用中设置），它似乎将列连接在一起，然后制作所有数据的小提琴图）
