Javascript 未捕获的 SyntaxError：JSON.parse 处的 JSON 输入意外结束（<匿名>）
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Uncaught SyntaxError: Unexpected end of JSON input at JSON.parse (<anonymous>)
提问by Ameur Baccoucha
I need some help with this error :
我需要一些帮助来解决这个错误：
Uncaught SyntaxError: Unexpected end of JSON input at JSON.parse () at Object.success (dashboard.js:22) at fire (jquery-3.3.1.js:3268) at Object.fireWith [as resolveWith] (jquery-3.3.1.js:3398) at done (jquery-3.3.1.js:9305) at XMLHttpRequest. (jquery-3.3.1.js:9548)
未捕获的 SyntaxError：在 Object.success (dashboard.js:22) at fire (jquery-3.3.1.js:3268) at Object.fireWith [as resolveWith] (jquery-3.3) 处 JSON.parse () 处的 JSON 输入意外结束.1.js:3398) 在完成 (jquery-3.3.1.js:9305) 在 XMLHttpRequest。(jquery-3.3.1.js:9548)
i try to transform a string to a json object using Json.parse()that cause that error. I am using oracleJet and this is my code:
我尝试使用导致该错误的Json.parse()将字符串转换为 json 对象。我正在使用 oracleJet，这是我的代码：
function DashboardViewModel() {
var self = this;
self.lineTypeValue = ko.observable('curved');
var scatterSeries = [];
$.getJSON( "http://localhost:8080/points", function (data) {
console.info(data);
var ch = '{"name":"graphe1","items":'+JSON.stringify(data.results[1])+ '}';
console.info(ch);
console.info(JSON.parse(scatterSeries));
scatterSeries.push(JSON.parse(ch));
});
/* chart data */
this.scatterSeriesValue = ko.observableArray(scatterSeries);
self.lineTypeOptions = [
{id: 'straight', label: 'straight'},
{id: 'curved', label: 'curved'},
{id: 'stepped', label: 'stepped'},
{id: 'segmented', label: 'segmented'},
{id: 'none', label: 'none'}
];
}
The Json that i get from "http://localhost:8080/points"look like this:
我从“ http://localhost:8080/points”得到的 Json看起来像这样：
{ "results":[
[
{
"b":"0.110547334",
"cost":"0.000000",
"w":"1.998889"
}
],
[
{
"x":0,
"y":0
},
{
"x":1,
"y":2
},
{
"x":2,
"y":4
},
{
"x":3,
"y":6
},
{
"x":4,
"y":8
},
{
"x":5,
"y":10
},
{
"x":6,
"y":12
},
{
"x":7,
"y":14
},
{
"x":8,
"y":16
},
{
"x":9,
"y":18
},
{
"x":10,
"y":20
},
{
"x":11,
"y":22
},
{
"x":12,
"y":24
},
{
"x":13,
"y":26
},
{
"x":14,
"y":28
},
{
"x":15,
"y":30
},
{
"x":16,
"y":32
},
{
"x":17,
"y":34
},
{
"x":18,
"y":36
},
{
"x":19,
"y":38
},
{
"x":20,
"y":40
},
{
"x":21,
"y":42
},
{
"x":22,
"y":44
},
{
"x":23,
"y":46
},
{
"x":24,
"y":48
},
{
"x":25,
"y":50
},
{
"x":26,
"y":52
},
{
"x":27,
"y":54
},
{
"x":28,
"y":56
},
{
"x":29,
"y":58
},
{
"x":30,
"y":60
},
{
"x":31,
"y":62
},
{
"x":32,
"y":64
},
{
"x":33,
"y":66
},
{
"x":34,
"y":68
},
{
"x":35,
"y":70
},
{
"x":36,
"y":72
},
{
"x":37,
"y":74
},
{
"x":38,
"y":76
},
{
"x":39,
"y":78
},
{
"x":40,
"y":80
},
{
"x":41,
"y":82
},
{
"x":42,
"y":84
},
{
"x":43,
"y":86
},
{
"x":44,
"y":88
},
{
"x":45,
"y":90
},
{
"x":46,
"y":92
},
{
"x":47,
"y":94
},
{
"x":48,
"y":96
},
{
"x":49,
"y":98
},
{
"x":50,
"y":100
},
{
"x":51,
"y":102
},
{
"x":52,
"y":104
},
{
"x":53,
"y":106
},
{
"x":54,
"y":108
},
{
"x":55,
"y":110
},
{
"x":56,
"y":112
},
{
"x":57,
"y":114
},
{
"x":58,
"y":116
},
{
"x":59,
"y":118
},
{
"x":60,
"y":120
},
{
"x":61,
"y":122
},
{
"x":62,
"y":124
},
{
"x":63,
"y":126
},
{
"x":64,
"y":128
},
{
"x":65,
"y":130
},
{
"x":66,
"y":132
},
{
"x":67,
"y":134
},
{
"x":68,
"y":136
},
{
"x":69,
"y":138
},
{
"x":70,
"y":140
},
{
"x":71,
"y":142
},
{
"x":72,
"y":144
},
{
"x":73,
"y":146
},
{
"x":74,
"y":148
},
{
"x":75,
"y":150
},
{
"x":76,
"y":152
},
{
"x":77,
"y":154
},
{
"x":78,
"y":156
},
{
"x":79,
"y":158
},
{
"x":80,
"y":160
},
{
"x":81,
"y":162
},
{
"x":82,
"y":164
},
{
"x":83,
"y":166
},
{
"x":84,
"y":168
},
{
"x":85,
"y":170
},
{
"x":86,
"y":172
},
{
"x":87,
"y":174
},
{
"x":88,
"y":176
},
{
"x":89,
"y":178
},
{
"x":90,
"y":180
},
{
"x":91,
"y":182
},
{
"x":92,
"y":184
},
{
"x":93,
"y":186
},
{
"x":94,
"y":188
},
{
"x":95,
"y":190
},
{
"x":96,
"y":192
},
{
"x":97,
"y":194
},
{
"x":98,
"y":196
},
{
"x":99,
"y":198
}
]]}
and what i want the variable scatterSeriesto hold is a table like this one:
我希望变量scatterSeries保存的是一张这样的表：
[ {
name:"graphe1",
items:[
{
x:8,
y:2
},
{
x:15,
y:15
},
{
x:25,
y:26
},
{
x:33,
y:22
},
{
x:36,
y:40
}
]},]
what i get in the console about the string chis this:
我在控制台中得到的关于字符串ch 的信息是这样的：
{"name":"graphe1","items":[{"x":0,"y":0},{"x":1,"y":2},{"x":2,"y":4},{"x":3,"y":6},{"x":4,"y":8},{"x":5,"y":10},{"x":6,"y":12},{"x":7,"y":14},{"x":8,"y":16},{"x":9,"y":18},{"x":10,"y":20},{"x":11,"y":22},{"x":12,"y":24},{"x":13,"y":26},{"x":14,"y":28},{"x":15,"y":30},{"x":16,"y":32},{"x":17,"y":34},{"x":18,"y":36},{"x":19,"y":38},{"x":20,"y":40},{"x":21,"y":42},{"x":22,"y":44},{"x":23,"y":46},{"x":24,"y":48},{"x":25,"y":50},{"x":26,"y":52},{"x":27,"y":54},{"x":28,"y":56},{"x":29,"y":58},{"x":30,"y":60},{"x":31,"y":62},{"x":32,"y":64},{"x":33,"y":66},{"x":34,"y":68},{"x":35,"y":70},{"x":36,"y":72},{"x":37,"y":74},{"x":38,"y":76},{"x":39,"y":78},{"x":40,"y":80},{"x":41,"y":82},{"x":42,"y":84},{"x":43,"y":86},{"x":44,"y":88},{"x":45,"y":90},{"x":46,"y":92},{"x":47,"y":94},{"x":48,"y":96},{"x":49,"y":98},{"x":50,"y":100},{"x":51,"y":102},{"x":52,"y":104},{"x":53,"y":106},{"x":54,"y":108},{"x":55,"y":110},{"x":56,"y":112},{"x":57,"y":114},{"x":58,"y":116},{"x":59,"y":118},{"x":60,"y":120},{"x":61,"y":122},{"x":62,"y":124},{"x":63,"y":126},{"x":64,"y":128},{"x":65,"y":130},{"x":66,"y":132},{"x":67,"y":134},{"x":68,"y":136},{"x":69,"y":138},{"x":70,"y":140},{"x":71,"y":142},{"x":72,"y":144},{"x":73,"y":146},{"x":74,"y":148},{"x":75,"y":150},{"x":76,"y":152},{"x":77,"y":154},{"x":78,"y":156},{"x":79,"y":158},{"x":80,"y":160},{"x":81,"y":162},{"x":82,"y":164},{"x":83,"y":166},{"x":84,"y":168},{"x":85,"y":170},{"x":86,"y":172},{"x":87,"y":174},{"x":88,"y":176},{"x":89,"y":178},{"x":90,"y":180},{"x":91,"y":182},{"x":92,"y":184},{"x":93,"y":186},{"x":94,"y":188},{"x":95,"y":190},{"x":96,"y":192},{"x":97,"y":194},{"x":98,"y":196},{"x":99,"y":198}]}
Any help please?!! :( :(
请问有什么帮助吗？！！:( :(
回答by Quentin
You are calling:
您正在致电：
JSON.parse(scatterSeries)
But when you defined scatterSeries, you said:
但是当你定义时scatterSeries，你说：
var scatterSeries = [];
When you try to parse it as JSON it is converted to a string (""), which is empty, so you reach the end of the string before having any of the possible content of a JSON text.
当您尝试将其解析为 JSON 时，它会转换为字符串 ( "")，该字符串为空，因此您在获得 JSON 文本的任何可能内容之前到达字符串的末尾。
scatterSeriesis not JSON. Do not try to parse it as JSON.
scatterSeries不是 JSON。不要尝试将其解析为 JSON。
datais not JSON either (getJSONwill parse it as JSON automatically).
data也不是 JSON（getJSON会自动将其解析为 JSON）。
chis JSON … but shouldn't be. You should just create a plain object in the first place:
ch是 JSON……但不应该是。您应该首先创建一个普通对象：
var ch = {
"name": "graphe1",
"items": data.results[1]
};
scatterSeries.push(ch);
In short, for what you are doing, you shouldn't have JSON.parseanywhere in your code. The only place it should be is in the jQuery library itself.
简而言之，对于你正在做的事情，你JSON.parse的代码中不应该有任何地方。它应该存在的唯一位置是 jQuery 库本身。
回答by Naga Sai A
Issue is with the Json.parse of empty array - scatterSeries , as you doing console log of scatterSeries before pushing ch
问题在于空数组的 Json.parse - scatterSeries ，因为您在推送 ch 之前执行 scatterSeries 的控制台日志
var data = { "results":[
[
{
"b":"0.110547334",
"cost":"0.000000",
"w":"1.998889"
}
],
[
{
"x":0,
"y":0
},
{
"x":1,
"y":2
},
{
"x":2,
"y":4
},
{
"x":3,
"y":6
},
{
"x":4,
"y":8
},
{
"x":5,
"y":10
},
{
"x":6,
"y":12
},
{
"x":7,
"y":14
},
{
"x":8,
"y":16
},
{
"x":9,
"y":18
},
{
"x":10,
"y":20
},
{
"x":11,
"y":22
},
{
"x":12,
"y":24
},
{
"x":13,
"y":26
},
{
"x":14,
"y":28
},
{
"x":15,
"y":30
},
{
"x":16,
"y":32
},
{
"x":17,
"y":34
},
{
"x":18,
"y":36
},
{
"x":19,
"y":38
},
{
"x":20,
"y":40
},
{
"x":21,
"y":42
},
{
"x":22,
"y":44
},
{
"x":23,
"y":46
},
{
"x":24,
"y":48
},
{
"x":25,
"y":50
},
{
"x":26,
"y":52
},
{
"x":27,
"y":54
},
{
"x":28,
"y":56
},
{
"x":29,
"y":58
},
{
"x":30,
"y":60
},
{
"x":31,
"y":62
},
{
"x":32,
"y":64
},
{
"x":33,
"y":66
},
{
"x":34,
"y":68
},
{
"x":35,
"y":70
},
{
"x":36,
"y":72
},
{
"x":37,
"y":74
},
{
"x":38,
"y":76
},
{
"x":39,
"y":78
},
{
"x":40,
"y":80
},
{
"x":41,
"y":82
},
{
"x":42,
"y":84
},
{
"x":43,
"y":86
},
{
"x":44,
"y":88
},
{
"x":45,
"y":90
},
{
"x":46,
"y":92
},
{
"x":47,
"y":94
},
{
"x":48,
"y":96
},
{
"x":49,
"y":98
},
{
"x":50,
"y":100
},
{
"x":51,
"y":102
},
{
"x":52,
"y":104
},
{
"x":53,
"y":106
},
{
"x":54,
"y":108
},
{
"x":55,
"y":110
},
{
"x":56,
"y":112
},
{
"x":57,
"y":114
},
{
"x":58,
"y":116
},
{
"x":59,
"y":118
},
{
"x":60,
"y":120
},
{
"x":61,
"y":122
},
{
"x":62,
"y":124
},
{
"x":63,
"y":126
},
{
"x":64,
"y":128
},
{
"x":65,
"y":130
},
{
"x":66,
"y":132
},
{
"x":67,
"y":134
},
{
"x":68,
"y":136
},
{
"x":69,
"y":138
},
{
"x":70,
"y":140
},
{
"x":71,
"y":142
},
{
"x":72,
"y":144
},
{
"x":73,
"y":146
},
{
"x":74,
"y":148
},
{
"x":75,
"y":150
},
{
"x":76,
"y":152
},
{
"x":77,
"y":154
},
{
"x":78,
"y":156
},
{
"x":79,
"y":158
},
{
"x":80,
"y":160
},
{
"x":81,
"y":162
},
{
"x":82,
"y":164
},
{
"x":83,
"y":166
},
{
"x":84,
"y":168
},
{
"x":85,
"y":170
},
{
"x":86,
"y":172
},
{
"x":87,
"y":174
},
{
"x":88,
"y":176
},
{
"x":89,
"y":178
},
{
"x":90,
"y":180
},
{
"x":91,
"y":182
},
{
"x":92,
"y":184
},
{
"x":93,
"y":186
},
{
"x":94,
"y":188
},
{
"x":95,
"y":190
},
{
"x":96,
"y":192
},
{
"x":97,
"y":194
},
{
"x":98,
"y":196
},
{
"x":99,
"y":198
}
]]};
var scatterSeries = [];
var ch = '{"name":"graphe1","items":'+JSON.stringify(data.results[1])+ '}';
console.info(ch);
scatterSeries.push(JSON.parse(ch));
console.info(scatterSeries);code sample - https://codepen.io/nagasai/pen/GGzZVB
回答by Tamas Hegedus
You define var scatterSeries = [];, and then try to parse it as a json string at console.info(JSON.parse(scatterSeries));which obviously fails. The variable is converted to an empty string, which causes an "unexpected end of input" error when trying to parse it.
您定义var scatterSeries = [];，然后尝试将其解析为console.info(JSON.parse(scatterSeries));显然失败的 json 字符串。该变量被转换为空字符串，这会在尝试解析它时导致“意外的输入结束”错误。
回答by pegasuspect
Remove this line from your code:
从您的代码中删除此行：
console.info(JSON.parse(scatterSeries));
