C语言 创建指向文件的指针数组
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create array of pointers to files
提问by Hristo
How would I go about making an array of file pointers in C?
I would like to create an array of file pointers to the arguments of main... like a1.txt, a2.txt, etc... So I would run ./prog arg1.txt arg2.txt arg3.txtto have the program use these files.
Then the argument for main is char **argv
我将如何在 C 中制作文件指针数组？
我想创建一个指向 main 参数的文件指针数组……比如 a1.txt、a2.txt 等……所以我会运行./prog arg1.txt arg2.txt arg3.txt让程序使用这些文件。
那么 main 的参数是char **argv
From argv, I would like to create the array of files/file pointers. This is what I have so far.
从 argv，我想创建文件/文件指针数组。这是我到目前为止。
FILE *inputFiles[argc - 1];
int i;
for (i = 1; i < argc; i++)
inputFiles[i] = fopen(argv[i], "r");
回答by kennytm
The code is fine, but remember to compile in C99.
代码没问题，但记得用C99编译。
If you don't use C99, you need to create the array on heap, like:
如果不使用 C99，则需要在堆上创建数组，例如：
FILE** inputFiles = malloc(sizeof(FILE*) * (argc-1));
// operations...
free(inputFiles);
回答by Arthur Kalliokoski
#include <stdio.h>`
int main(int argc, char **argv)
{
FILE *inputFiles[argc - 1];
int i;
for (i = 1; i < argc; i++)
{
printf("%s\n",argv[i]);
inputFiles[i] = fopen(argv[i], "r");
printf("%p\n",inputFiles[i]);
}
return 0;
}
It prints different pointers for each file pointer along with the names. Allowing OS to close files properly :)
它为每个文件指针以及名称打印不同的指针。允许操作系统正确关闭文件:)
