在 bash 脚本中获取调用者脚本的名称
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Get the name of the caller script in bash script
提问by a14m
Let's assume I have 3 shell scripts:
假设我有 3 个 shell 脚本：
script_1.sh
脚本_1.sh
#!/bin/bash
./script_3.sh
script_2.sh
脚本_2.sh
#!/bin/bash
./script_3.sh
the problem is that in script_3.shI want to know the name of the caller script.
问题是script_3.sh我想知道调用者脚本的名称。
so that I can respond differently to each caller I support
这样我就可以对我支持的每个来电者做出不同的回应
please don't assume I'm asking about $0cause $0will echo script_3every time no matter who is the caller
请不要以为我问$0原因$0会响应script_3每一次不管是谁来电
here is an example input with expected output
这是一个具有预期输出的示例输入
./script_1.shshould echoscript_1./script_2.shshould echoscript_2./script_3.shshould echouser_name or root or anything to distinguish between the 3 cases?
./script_1.sh应该回声script_1./script_2.sh应该回声script_2./script_3.sh应该回声user_name or root or anything to distinguish between the 3 cases？
Is that possible? and if possible, how can it be done?
那可能吗？如果可能的话，怎么做？
this is going to be added to a rmmodified script... so when I call rmit do something and when gitor any other CLI tool use rmit is not affected by the modification
这将被添加到rm修改后的脚本中......所以当我调用rm它时做一些事情并且当git或任何其他 CLI 工具使用rm它时它不受修改的影响
回答by Thomas Guyot-Sionnest
Based on @user3100381's answer, here's a much simpler command to get the same thing which I believe should be fairly portable:
基于@user3100381 的回答，这里有一个更简单的命令来获得我认为应该相当便携的东西：
PARENT_COMMAND=$(ps -o comm= $PPID)
Replace comm=with args=to get the full command line (command + arguments). The =alone is used to suppress the headers.
更换comm=用args=得到完整的命令行（命令+参数）。该=单独用来抑制头。
See: http://pubs.opengroup.org/onlinepubs/009604499/utilities/ps.html
请参阅：http: //pubs.opengroup.org/onlinepubs/009604499/utilities/ps.html
回答by user3100381
The $PPID variable holds the parent process ID. So you could parse the output from ps to get the command.
$PPID 变量保存父进程 ID。所以你可以解析 ps 的输出来获取命令。
#!/bin/bash
PARENT_COMMAND=$(ps $PPID | tail -n 1 | awk "{print $5}")
回答by Kashyap
In case you are sourceing instead of calling/executing the script there is no new process forked and thus the solutions with pswon't work reliably.
如果您是sourceing 而不是调用/执行脚本，则没有新进程分叉，因此解决方案ps将无法可靠地工作。
Use bash built-in callerin that case.
caller在这种情况下使用内置的 bash 。
$ cat h.sh
#! /bin/bash
function warn_me() {
echo "$@"
caller
}
$ cat g.sh
#!/bin/bash
source h.sh
warn_me "Error: You didn't do something"
$ . g.sh
Error: You didn't do something 3
g.sh
$
回答by Gilles Quenot
Based on @J.L.answer, with more in depth explanations (the only one command that works for me (linux)) :
基于@JLanswer，有更深入的解释（唯一对我有用的命令（linux））：
cat /proc/$PPID/comm
gives you the name of the command of the parent pid
为您提供父pid命令的名称
If you prefer the command with all options, then :
如果您更喜欢带有所有选项的命令，那么：
cat /proc/$PPID/cmdline
explanations :
解释：
$PPIDis defined by the shell, it's the pidof the parent processes- in
/proc/, you have some dirs with the pidof each process (linux). Then, if youcat /proc/$PPID/comm, you echo the command name of the PID
Check man proc
检查man proc
回答by J.L.
If you have /proc:
如果你有/proc：
$(cat /proc/$PPID/comm)
回答by Reinstate Monica Please
Couple of useful files things kept in /proc/$PPID here
一些有用的文件保存在 /proc/$PPID 中
/proc/*some_process_id*/exeA symlink to the last executed command under *some_process_id*/proc/*some_process_id*/cmdlineA file containing the last executed command under *some_process_id* and null-byte separated arguments
/proc/*some_process_id*/exe*some_process_id* 下最后执行的命令的符号链接/proc/*some_process_id*/cmdline在 *some_process_id* 下包含最后执行的命令和空字节分隔参数的文件
So a slight simplification.
所以稍微简化一下。
sed 's/\x0/ /g' "/proc/$PPID/cmdline"
回答by Six
You can simply use the command below to avoid calling cut/awk/sed:
您可以简单地使用以下命令来避免调用 cut/awk/sed：
ps --no-headers -o command $PPID
If you only want the the parent and none of the subsequent processes, you can use:
如果您只需要父进程而不需要后续进程，则可以使用：
ps --no-headers -o command $PPID | cut -d' ' -f1
回答by Snehasish Sarkar
Declare this:
声明如下：
PARENT_NAME=`ps -ocomm --no-header $PPID`
Thus you'll get a nice variable $PARENT_NAME that holds the parent's name.
因此你会得到一个很好的变量 $PARENT_NAME ，它保存了父母的名字。
回答by Donovan
You could pass in a variable to script_3.sh to determine how to respond...
您可以将变量传递给 script_3.sh 以确定如何响应...
script_1.sh
脚本_1.sh
#!/bin/bash
./script_3.sh script1
script_2.sh
脚本_2.sh
#!/bin/bash
./script_3.sh script2
script_3.sh
脚本_3.sh
#!/bin/bash
if [ == 'script1' ] ; then
echo "we were called from script1!"
elsif [ == 'script2' ] ; then
echo "we were called from script2!"
fi
